Explanation:
Given parameters:
Mass of the weight = 15kg
Height of bar lift = 0.25m
Number of times lifted = 15times
Unknown:
Total height the bar was lifted = ?
Force needed for the lift = ?
Work done = ?
Solution:
To solve this problem we need to understand that;
Work done = Force x distance
Work done = mass x acceleration due gravity x height
Work done = weight x height
a. Total height:
Total height = 0.25 x 15 = 3.75m
b. Force needed ;
Force needed = Weight of bar = mass x gravity
= 15 x 9.8 = 147N
So;
Force used for the 15 times = 15 x 147 = 2205N
c. Work done ;
Work done = weight x height = 2205 x 3.75 = 8268.75J
Looks right to me? Pls mark brainliest if correct
Answer:
7.8% of the original volume.
Explanation:
From the given information:
Temperature = 22° C = 273 + 22 = 295° C
Pressure = 240 kPa
Temperature = 45° C
At initial temperature and pressure:
Using the ideal gas equation:
making V_1 (initial volume) the subject:
Provided the pressure maintained its rate at 240 kPa, when the temperature reached 45° C, then:
the final volume can be computed as:
Now, the change in the volume ΔV = V₂ - V₁
∴
The required fraction of the volume of air to keep up the pressure at (240) kPa can be computed as:
= 7.8% of the original volume.
Answer:
Explanation:
The distance is the same in the experiment and using the differents times can find the velocities so
Now the experiment can use the equations of tension in simple pendulum
Now to determinate the mass using the formula of force of gravity
Solve to Mm
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