Answer:
The horse is going at 12.72 m/s speed.
Explanation:
The initial speed of the horse (u) = 3 m/s
The acceleration of the horse (a)= 5 m/
The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m
Applying the second equation of motion to find out the time,
Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.
Now applying first equation of motion, to find out the final velocity,
v=12.72 m/s
The horse travels at a speed of 12.72 m/s after covering the given distance.
Here Power = Voltage * Current
So, Voltage = Power/Current
Put the values,
V = 240/2
V = 120 V
In short, Your Final Answer would be: 120 Volts
Hope this helps!
Answer:
7kgm/s
Explanation:
Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.
Let P1A and P1B be the initial momentum of the bodies A and B respectively
Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.
Based on the law:
P1A+P2A = P1B + P2B
Given P1A = 5kgm/s
P2A = 0kgm/s(ball B at rest before collision)
P2A = -2.0kgm/s (negative because it moves in the negative x direction)
P2B = ?
Substituting the values in the equation gives;
5+0 = -2+P2B
5+2 = P2B
P2B = 7kgm/s
Answer:
Final velocity at the top of the ramp is 6.58m/s
Explanation
Check the attachment
347÷134=2.589552239 meters per second
2.589552239×60= 155.3731343 meters per hour
155.3731343 meters per hour= 0.096544389701642 miles per hour
hopefully this was right.
