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12345 [234]
2 years ago
11

When discussing Newton’s laws of motion, which terms do people most likely use when talking about Newton’s third law of motion?

"force" and "acceleration" "inertia" and "force" "action" and "reaction" "mass" and "inertia"
Physics
2 answers:
mezya [45]2 years ago
6 0

Answer:

INERTIA

Explanation:

KatRina [158]2 years ago
4 0

Answer:

Action and reaction

Explanation:

Newton's third law states that for every action there is an equal and an opposite reaction. The pair of force exits there. The pair of force is "action and reaction".

For example, if you slap someone, then you also feel pain in your hand. If you slap someone then this is an action. You feel pain in your hand then it is a reaction.

Force and acceleration terms are related to Newton's second law of motion.

The relation between force and acceleration is as;        

F = ma

Here, m is the mass, F is the applied force and a is the acceleration.

Inertia and force terms are related to Newton's first law of motion.  Newton's first law of motion is also known as the law of inertia. Inertia is a tendency to remain in a state unchanged.

Therefore, the "action and reaction" terms are related to Newton's third of motion.

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What is causing the boat to move toward the shore?
ivann1987 [24]

Answer:c

Explanation:because when u push the oar back u go forward

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3 years ago
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A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process? A. velocity and
dezoksy [38]

Answer:

A. velocity and wavelength

Explanation:

  • When a wave travels from one medium to another it undergoes a change in direction and this is referred to as refraction.
  • Refraction is the bending of a wave or a change in direction of a wave as it travels from one medium to another. Refraction is accompanied by change in velocity and wavelength of a wave.
  • Velocity of a wave is proportional to the wavelength of the wave therefore, if the velocity of a wave changes the the wavelength will also change proportionally to the velocity.
5 0
3 years ago
The combination of an applied force and a friction force produces a constant total torque of 35.5 N · m on a wheel rotating abou
Cerrena [4.2K]

Answer:

a) I = 19.799\,kg\cdot m^{2}, b) T = -3.405\,N\cdot m, c) n_{T} \approx 54.842\,rev

Explanation:

a) The net torque is:

T = I\cdot \alpha

Let assume a constant angular acceleration, which is:

\alpha = \frac{\omega-\omega_{o}}{t}

\alpha = \frac{10.4\,\frac{rad}{s} - 0\,\frac{rad}{s} }{5.80\,s}

\alpha = 1.793\,\frac{rad}{s^{2}}

The moment of inertia of the wheel is:

I = \frac{T}{\alpha}

I = \frac{35.5\,N\cdot m}{1.793\,\frac{rad}{s^{2}} }

I = 19.799\,kg\cdot m^{2}

b) The deceleration of the wheel is due to the friction force. The deceleration is:

\alpha = \frac{\omega-\omega_{o}}{t}

\alpha = \frac{0\,\frac{rad}{s} - 10.4\,\frac{rad}{s}}{60.4\,s}

\alpha = - 0.172\,\frac{rad}{s^{2}}

The magnitude of the torque due to friction:

T = (19.799\,kg\cdot m^{2})\cdot (-0.172\,\frac{rad}{s^{2}} )

T = -3.405\,N\cdot m

c) The total angular displacement is:

\theta_{T} = \theta_{1} + \theta_{2}

\theta_{T} = \frac{(10.4\,\frac{rad}{s} )^{2}-(0\,\frac{rad}{s} )^{2}}{2\cdot (1.793\,\frac{rad}{s^{2}} )} + \frac{(0\,\frac{rad}{s} )^{2}-(10.4\,\frac{rad}{s} )^{2}}{2\cdot (-0.172\,\frac{rad}{s^{2}} )}

\theta_{T} = 344.580\,rad

The total number of revolutions of the wheel is:

n_{T} = \frac{\theta_{T}}{2\pi}

n_{T} = \frac{344.580\,rad}{2\pi}

n_{T} \approx 54.842\,rev

5 0
3 years ago
A charged point particle is placed at the center of a spherical gaussian surface. the electric flux is changed if:
ololo11 [35]

The electric flux is changed only if we change the charge.

<h3>What is the expression of electric flux?</h3>
  • As per gauss law, total electric flux link through a surface is equal to (1/ε0) × charge.
  • Mathematically, electric flux = q/ε0
  • q = total charge enclosed by the gaussian surface
  • Here the electric flux is directly proportional to the charge, so on changing charge, the electric flux changes.

Thus, we can conclude that the electric flux is changed only if we change the charge.

Learn more about the gauss law here:

brainly.com/question/13434428

#SPJ1

3 0
2 years ago
Based on the information you know about friction discuss with your group how you could experimentally determine the coefficient
Alona [7]

Answer:

The experiment to determine the coefficient of static friction between a rough block and an incline plane is detailed in the explanation.

Explanation:

A simple experiment is as follows:

Take a weight in which its mass is known and hold it with a roller at the end of the inclined plane with a rope.

Place the weight on the plane inclined horizontally with the ground, forming a zero degree angle.

Gradually lift the weight so that the angle of incline begins to increase.

Observe that the weight will begin to slide. This angle will be the angle theta.

In this way, the coefficient of friction will be calculated as the tangent of the angle theta.

Take a different weight and repeat the procedure to get different values ​​of the coefficient of friction.

By averaging the coefficients of friction, a final value will be obtained.

5 0
2 years ago
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