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3 years ago

9

The size of a TV is the diagonal measurement of its screen. Will a 46-inch TV fit in a rectangular cabinet measuring 32 inches l

ong and 28 inches
high? Explain

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

sdrfffffffffsdffffffffffffffffsdffffffffffffffffffffffffffffdssss

Step-by-step explanation:

dfssssssssssssssssssssssssssssssssssssss

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I need an answer right now

amm1812

Answer:

Step-by-step explanation:

(1x/4 + 1/7) + (3x/8 - 1/3) = x/4 + 3x/8 + 1/7 - 1/3

= x*2/4*2 + 3x/8 + 1*3/7*3 - 1*7/3*7

= 2x/8 + 3x/8 + 3/21 - 7/21

= (2x+3x)/8 + (3-7) /21

= 5x/8 + (-4)/21

= 5x/8 - 4/21

8 0

3 years ago

If the outliers are not included, what is the mean of the data set?

ioda

If you don't include the outlier (50) then it is 79.7

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3 years ago

Read 2 more answers

For spring break this year your family decided to visit Michigan, but it snows the first weekend you are there. You decide to ma

Nataly [62]

V = 4/3 (pi r times ^3) = formula for this knowing that you than

Combine volumes up (1ft times 3.14) + (2ft times 3.14) + (3ft times 3.14)

18.8 >. rounded to the nearest cubic foot of 19

8 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

IN ΔBCD line N is the perpendicular bisector of BC and line M is the perpendicular bisector of CD

Helga [31]

Answer:

Correct answer is D(the intersection of lines N and M)

Step-by-step explanation:

we Know that circumcenter of a triangle is point at which the perpendicular bisectors of the sides of a triangle intersect and which is equidistant from the three vertices. In other words circumcenter of a triangle is the center of the circle which passes through the vertices of the triangle. It means, any side of the triangle will act as a chord of the circumcircle. Hence the circumcenter of a triangle must lie on the perpendicular bisectors of the sides. therefore the intersection of line N and M must be circumcenter of the triangle.

I hope this answer will help you

4 0

3 years ago