Answer:
(a) The speed of the target proton after the collision is:, and (b) the speed of the projectile proton after the collision is: .
Explanation:
We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle:, and y axle:. Now replacing the value given as: , for the projectile proton and according to the problem are perpendicular so , and assuming that , we get for x axle: and y axle: , then solving for , we get: and replacing at the first equation we get:, now solving for , we can find the speed of the projectile proton after the collision as: and , that is the speed of the target proton after the collision.
Answer;
-Gases
Explanation;
-Pressure can affect the density of gases.
-Density of gases changes with pressure and temperature because gases are compressible fluid and because they are compressible, when pressure increases molecules come closer to each other which means increase in density and when pressure drops molecules of gases become free to expand and get away from each other which density decrease.
“a point representing the mean position of the matter in a body or system.”
The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration towards the ground. So we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:
Learn more about free fall:
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