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MakcuM [25]
3 years ago
14

Please help asap! Thank you.

Physics
2 answers:
Leviafan [203]3 years ago
8 0
The answer is C-Direct Current
olganol [36]3 years ago
4 0

Answer:

direct current

Explanation:

it has a direct path to go down to reach the specific point

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A circuit featuring multiple paths through which current can flow is best classified into which category?
Rina8888 [55]
A parallel circuit - there are multiple branches at which current is able to to be pushed around the circuit.
4 0
3 years ago
Read 2 more answers
If the pressure exerted on a 300.0 mL sample of hydrogen gas at constant temperature is increased from 0.500 kPa to 0.750 kPa, w
uranmaximum [27]

Answer:

200 mL

Explanation:

Given that,

Initial volume, V₁ = 300 mL

Initial pressure, P₁ = 0.5 kPa

Final pressure, P₂ = 0.75 kPa

We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2

V₂ is the final volume

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{300\times 0.5}{0.75}\\\\V_2=200\ mL

So, the final volume of the sample is 200 mL.

5 0
3 years ago
A 0.035 bullet strikes a 5kg wooden block that is stationary and gets stuck inside the block. The block and bullet move together
hjlf

Answer:

1240 m/s

Explanation:

[Do you mean 0.035 kg bullet?]

Since the momentum of the system is conserved,

Let u m/s be the initial velocity of the bullet

0.035u = 8.6(5+0.035)

u ~= 1237.1714 m/s

u = 1240 m/s (3 sig. fig.)

7 0
3 years ago
10 kg box accelerates at 2 meters per second as it slides down a ramp at an angle of 25 degrees. What is the coefficient of fric
maria [59]

Answer:

0.241

Explanation:

resolving weight into two components and calculating force of friction in terms of coefficient of friction and then applying Newton 's law we get the value .This all has been explained in attachment

Download pdf
3 0
3 years ago
An electron is moving through an (almost) empty universe at a speed of 628 km,/s toward the only other object in the universe —
sattari [20]

Answer:

  r = 2,026 10⁹ m  and   T = 2.027 10⁴ s

Explanation:

For this exercise let's use Newton's second law

        F = m a

where the force is electric

        F = k \frac{q_1q_2}{r^2}

Acceleration is centripetal

        a = v² / r

we substitute

        k \frac{q_1q_2}{r^2} = m \frac{v^2}{r}

        r = k \frac{q_1q_2}{m \  v^2}          (1)

let's look for the charge in the insulating sphere

          ρ = q₂ / V

          q₂ = ρ V

the volume of the sphere is

         v = 4/3 π r³

we substitute

        q₂ = ρ \frac{4}{3} π r³

        q₂ = 3 10⁻⁹ \frac{4}{3} π 4³

        q₂ = 8.04 10⁻⁷ C

let's calculate the radius with equation 1

        r = 9 10⁹  1.6 10⁻¹⁹  8.04 10⁻⁷ /(9.1  10⁻³¹ 628 10³)

        r = 2,026 10⁹ m

this is the radius of the electron orbit around the charged sphere.

Since the orbit is circulating, the speed (speed modulus) is constant, we can use the uniform motion ratio

        v = x / t

the distance traveled in a circle is

        x = 2π r

In this case, time is the period

        v = 2π r /T

        T = 2π r /v

let's calculate

        T = 2π 2,026 10⁹/628 103

        T = 2.027 10⁴ s

4 0
3 years ago
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