Answer:
any object that has density more than 1.4
Explanation:
The object that has density more than 1.4 is denser than the honey
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Answer
given,
For helium
Volume,V = 46 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₁ = ?
number of moles
we know
P V = n R T
![n_1 =\dfrac{46 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_1%20%3D%5Cdfrac%7B46%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₁ = 1.89 moles
For oxygen
Volume,V = 12 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₂ = ?
number of moles
we know
P V = n R T
![n_2 =\dfrac{12 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_2%20%3D%5Cdfrac%7B12%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₂ = 0.49 moles
Total volume of tank = 5 L
temperature of tank = 298 K
Partial pressure of helium
![P_1=\dfrac{n_1 R T}{V}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7Bn_1%20R%20T%7D%7BV%7D)
![P_1=\dfrac{1.89\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B1.89%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₁ = 9.25 atm
Partial pressure of oxygen
![P_2=\dfrac{n_2 R T}{V}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7Bn_2%20R%20T%7D%7BV%7D)
![P_2=\dfrac{0.49\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B0.49%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₂ = 2.39 atm
total pressure
P = P₁ + P₂
P = 9.25 + 2.39
P = 11.64 atm