If the value of "y" varies directly with "X"<br> and y = -8 when x = 20, find "y" if x = -4.

Can anyone help me with these i need them befire tomorrow

mash [69]

When you have a scale factor as percentage, is better to convert that percentage into a fraction by divide it by 100%. That way, it will be much easier to scale your figures.

1. The scale factor we need to apply to our rectangle is 60%. Firts, lets convert our scale factor into a fraction: $\frac{60}{100} = \frac{3}{5}$ . Next, we just need to multiply each side of our rectangle by our fraction:
length= $16( \frac{3}{5})=9.6$
width= $8( \frac{3}{5} )=4.8$
So, our new rectangle will have a length of 9.6 units and a width of 4.8 units.

2. This time the scale factor is 120%. Just as before, lets convert it into a fraction: $\frac{120}{100} = \frac{6}{5}$ , and just as before lets multiply each side of our triangle by our fraction:
base= $10( \frac{6}{5} )=12$
side= $8( \frac{6}{5} )=9.6$
So, our new isosceles triangle will have a base of 12 units and tow sides of length 9.6 units each.

3. This time the scale factor is 150%. Just as before, lets convert it into a fraction: $\frac{150}{100} = \frac{3}{2}$ , and just as before lets multiply each side of our polygon by our fraction:
$12( \frac{3}{2} )=18$
$15( \frac{3}{2} )=22.5$
$13( \frac{3}{2} )=19.5$
So, our new polygon will have a side of 12 length units, tow sides of 15 length units, and two side of 15 length units.

4. This time our factor is 75%. Just as before, lets convert it into a fraction: $\frac{75}{100} = \frac{3}{4}$ , and just as before lets multiply each side of our parallelogram by our fraction:
side= $25( \frac{3}{4} )=18.75$
So, our new parallelogram will have tow sides of length 18.75 units.

7 0

3 years ago

a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re

Lemur [1.5K]

X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
10=4a
a=5/2

End equation:
Y=5/2*2^x

3 0

2 years ago

I need help with this question ASAP

IgorLugansk [536]

Answer:

The answer would be 49 I think hehe

Step-by-step explanation:

7 0

2 years ago

PLEASE HURRY IM TIMED, The perimeter of a rectangular swimming pool is 70 yards. Its length is 25 yards. Which of the following

kolezko [41]

I thik the option C should be used.

5 0

1 year ago

Read 2 more answers

Math workshops and final exams: The college tutoring center staff are considering whether the center should increase the number

oksian1 [2.3K]

Answer:

Option D

Step-by-step explanation:

The response variable is also known as the dependent variable. It depends on another factor which is the independent variable to cause change/ response to it.

In this study, they want to test if an increase in the number of Math workshop which is the independent variable will cause a change in the final exam scores which is the dependent variable. The response to this inquiry is thus the final exam score which is also known as the response variable.

7 0

2 years ago

If the value of "y" varies directly with "X" and y = -8 when x = 20, find "y" if x = -4.