This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

$P_1V_1=P_2V_2$

Thus, we solve for the final pressure, P2, to get:

$P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm$

Learn more about ideal gases: brainly.com/question/8711877

8 0

3 years ago

3 mL is equal to:<br><br> 3 L<br> 3 cm2<br> 3 cm3

Rufina [12.5K]

Answer:

3 cm3

Explanation:

1 L = 1 dm3 = 1000 mL (or 10^3 mL)

1 dm = 10 cm

1 dm3 = 10^3 cm

==> 1 mL = 1 cm3

Therefore, 3 cm3 = 3 mL

8 0

3 years ago