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daser333 [38]
3 years ago
13

When cadmium (Cd) is mixed with hydrochloric acid (HCI), a single-displacement reaction occurs.

Chemistry
2 answers:
navik [9.2K]3 years ago
8 0

Answer:is Cl and H

Explanation:

2Cd+2Hcl=2CdCl + H2

borishaifa [10]3 years ago
7 0
The answer is A on edmentum
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A solution with a pH level of 7.0 would be considered as an Basic, Acidic, or neutral
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Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)
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Answer:  a) Sodium and nitrogen : NaN_3  : sodium nitride.

b) Oxygen and strontium : SrO :  strontium oxide.

c) Aluminum and chlorine : AlCl_3  : aluminium chloride.

d) Cesium and bromine : CsBr  : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as Na^{+} cation and nitrogen forms an anion N^{3-} with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaN_3  named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as Sr^{+} cation and oxygen forms an anion O^{2-} with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral SrO  named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as Al^{3+} cation and chlorine forms an anion Cl^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral AlCl_3  named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as Cs^{+} cation and bromine forms an anion Br^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr  named as cesium bromide.

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{ \tt{1 \: km = 1000m}} \\ { \tt{1.5  \times {10}^{8} km =  (\frac{1.5 \times  {10}^{8} \times 1000 }{1} )m}} \\  = 1.5 \times  {10}^{11}  \: metres

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