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AlexFokin [52]
3 years ago
9

An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the

volume of the gas to 15 mL. What is the new pressure of the gas at this volume?
Chemistry
1 answer:
sukhopar [10]3 years ago
8 0

This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

P_1V_1=P_2V_2

Thus, we solve for the final pressure, P2, to get:

P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm

Learn more about ideal gases: brainly.com/question/8711877

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On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+
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Answer:

Acid(BSA) = CH₃COOH

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Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

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Explanation:

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4.55x10⁸ Pa * \frac{1torr}{133.322Pa} = 3.41 x10⁶ torr

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