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Margarita [4]
3 years ago
11

Adam's dad takes the parkway to work. It takes him 45 minutes to travel from mile marker 145 where he enters the parkway to his

exit at mile marker 98. what is his average speed. I do know it is not D.
A. 193.3
B. 62.7
C.1
D.47
Chemistry
1 answer:
BartSMP [9]3 years ago
5 0
This would be C, 1.044 mi/min
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What is the relationship between grams and cm³? ​
soldier1979 [14.2K]

Answer:

1 gram

Explanation:

1 gram= weight of 1 cubic centimeter of pure water at temperature 4°C = 1000 milligrams = 0.001 kilogram

3 0
2 years ago
g To what volume (in mL) should 5.07 mL of an 6.82 M acetic acid solution be diluted in order to obtain a final solution that is
denis-greek [22]

Answer:

The volume of the solution must be increased to 71.429 millimeters by adding 66.359 millimeters of solute to reduce molarity from 6.82 M to 0.49 M.

Explanation:

The molarity is a unit used for solution that is equivalent to the amount of moles of solute per unit volume of solution. That is:

M = \frac{n_{st}}{V_{sol}}

Where:

n_{st} - Amount of moles of solute, measured in moles.

V_{sol} - Volume of the solution, measured in liters.

To reduce the molarity of the solution, more millimeters of solvent should be added. Firstly, the amount of moles of acetic acid inside the 6.82 M solution needs to be determined (M_{o} = 6.82\,M and V_{sol} = 5.07\times 10^{-3}\,L):

n_{st} = M_{o}\cdot V_{sol}

n_{st} = (6.82\,M)\cdot (5.07\times 10^{-3}\,L)

n_{st} = 0.035\,mol

Now, the resulting volume of solution after diluting the acetic acid solution is: (M_{f} = 0.49\,M and n_{st} = 0.035\,mol):

V_{sol} = \frac{n_{st}}{M_{f}}

V_{sol} = \frac{0.035\,mol}{0.49\,M}

V_{sol} = 71.429\times 10^{-3}\,L

V_{sol} = 71.429\,mL (1 L = 1000 mL)

The amount of solvent needed to dilute the solution is:

\Delta V_{sol} = 71.429\times 10^{-3}\,L - 5.07\times 10^{-3}\,L

\Delta V_{sol} = 66.359 \times 10^{-3}\,L

\Delta V_{sol} = 66.359\,mL (1 L = 1000 mL)

The volume of the solution must be increased to 71.429 millimeters by adding 66.359 millimeters of solute to reduce molarity from 6.82 M to 0.49 M.

7 0
3 years ago
Molarity problem:
S_A_V [24]
Density = 1.0 g/mL

5.3 (w/w)% => 5.3 / 100 => 0.053

molar mass acetic acid = 60.05 g/mol

M = 1000.  w . D / molar mass

M = 1000 . 0.053 . 1.0 / 60.05

M = 53 / 60.05

M = 0.882 mol/L

hope this helps!
8 0
3 years ago
Read 2 more answers
Which of the following is a correct statement regarding the free energy?
Mnenie [13.5K]

Answer:

A

Explanation:

6 0
2 years ago
A sample of seawater consists of water, sodium ions, chloride ions, and several other dissolved salts. These ions and salts are
stellarik [79]

Answer:

Mixture, homogeneous mixture, solution

Explanation:

A mixture is defined as a substance which is made by physical combination of two or more substance.

As in sea water, more than two substance are present, therefore is considered as mixture.

A mixture is considered as homogeneous mixture, if it has same proportion of components through out the mixture. In sea water proportions of all the components are same, therefore, its is also a homogeneous mixture.

In solution, solute is dissolved in a solvent and the concentration of the solute is same through out the solution.. In sea water, sodium ions, chloride ions, and several other salts are dissolved in water. Therefore, water is considered as solvents and components present are considered as solute.

so, sea water can also considered as solution.

Among the given options, 1, 3 and 4 are correct

So, sea water is considered as mixture, homogeneous mixture and solution.

6 0
3 years ago
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