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harina [27]
3 years ago
6

Find the kinetic energy of the horse using KE=1/2 mv².

Chemistry
2 answers:
Dmitry [639]3 years ago
8 0
KE=6,250Joules
You plug in your given numbers and remember to square 5 because that’s the speed
zloy xaker [14]3 years ago
7 0

Answer:

6250

Explanation:

so m=500 and v=5

so v²=25

using the equation we can do 1/2 x 500 x 25 = 6250

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Ben is pushing a small trolley 10 N to the north and but Gary is pushing the trolley 5 N to the south. What is the total applied
andrew-mc [135]

Answer:

The total applied force on the trolley is 5 N toward the North.

Explanation:

In this problem, Ben is pushing the trolley to north and Gary is pushing it to south. So both the forces are acting 180° opposite to each other. As force is a vector quantity, the net force or total force acting on any object should be calculated by vector addition of number of forces along with their directions. So in this case, if we consider the force Ben is applying as F1 and the force Gary is applying as F2 on the trolley. Then the net or total force acting on the trolley will be F1-F2. This is because, F1 and F2 are acting opposite to each other in direction.Thus, Total force acting on the trolley = 10 N - 5 N.

So the total force acting on the trolley is 5 N and it is toward the north direction.

5 0
3 years ago
Help please with this tough question
Alla [95]

Answer:

  1. option B
  2. option A

Explanation:

please mark me as brainliest ❤️

5 0
3 years ago
What is a key element found in CO2 and glucose?
hram777 [196]
Carbon is the only possible solution in this question for the reason that the chemical formula for glucose is c6h12o6 (6, 12 and 6 underscore) and carbon dioxide is co2. Both of the chemical formula contains carbon that is why that is the main element. 
8 0
3 years ago
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There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the press
sertanlavr [38]

Answer:

\large \boxed{\text{D.) 91 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}

6 0
3 years ago
At a pressure of 1.76 atm and 305 K, a certain gas has a volume of 350.0 mL. What will be the new volume of this gas under STP.​
Maksim231197 [3]

Answer:

hi

Explanation:

I'm just figuring this out

4 0
3 years ago
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