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Brut [27]
2 years ago
7

Phân tích x³-6x²+11x-6

Mathematics
1 answer:
AlladinOne [14]2 years ago
4 0

Answer:

(x-1)(x-2)(x-3)

Step-by-step explanation:

hy vọng nó giúp

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Solve the equation for x, where x is a real number (5 points): <br> -2x^2 + 5x - 10 = 3
KatRina [158]
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                      x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
                                      x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
3 0
3 years ago
For what values of the variables are the following expressions defined? 1. 5y+2 2. 18/y 3. 1/x+7 4. 2b/10−b Example: X&gt;7
Serga [27]

Answer:

1. All real numbers

2. All real numbers except y = 0

3. All real numbers except x = -7

4. All real numbers except b = 10

Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em>\infty<em> or it should not give us the </em>\frac{0}{0}<em> (zero by zero) form </em> when the input is given to the function.

The value of function will depend on the denominator.

Now, let us consider the given functions one by one:

1. 5y+2

Here denominator is 1. So, it can not attain a value \infty or \frac{0}{0}<em> (zero by zero) form </em>

So, for all real numbers, the function is defined.

2.\ \dfrac{18}{y}

At y = 0, the value

At\ y =0,  \dfrac{18}{y} \rightarrow \infty

So, the given function is <em>defined for all real numbers except y = 0</em>

<em></em>

<em></em>3.\ \dfrac{1}{x+7}<em></em>

Let us consider denominator:

x + 7 can be zero at a value x = -7

At\ x =-7,  \dfrac{1}{x+7} \rightarrow \infty

So, the given function is <em>defined for all real numbers except x = -7</em>

<em></em>

4.\ \dfrac{2b}{10-b}

Let us consider denominator:

10-b can be zero at a value b = 10

At\ b =10,  \dfrac{2b}{10-b} \rightarrow \infty

So, the given function is <em>defined for all real numbers except b = 10</em>

<em></em>

7 0
3 years ago
I put the wrong picture on the last one but this is still due soon
fgiga [73]

Answer:

The point ”A“ is the point that corresponds to the last entry in the table.

Step-by-step explanation:

5 0
2 years ago
Dominick borrowed $6,000 from a credit union at 9% simple interest for 30 months. What were his monthly installment payments to
Lady_Fox [76]

<em>Answer: </em>

<em>A = $7,350.00</em>

<em></em>

<em>Step-by-step explanation:</em>

<em>Equation:</em>

<em>A = P(1 + rt)</em>

<em>First, converting R percent to r a decimal</em>

<em>r = R/100 = 9%/100 = 0.09 per year.</em>

<em>Putting time into years for simplicity,</em>

<em>30 months / 12 months/year = 2.5 years.</em>

<em></em>

<em></em>

<em>Solving our equation:</em>

<em>A = 6000(1 + (0.09 × 2.5)) = 7350 </em>

<em>A = $7,350.00</em>

<em>The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 9% per year for 2.5 years (30 months) is $7,350.00.</em>

<em>* Therefor, the answer is $7,350.00.</em>

<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>

7 0
3 years ago
A number of friends decided to go on a picnic and planned to spend rs. 96 on eatables. four of them, however, did not turn up. a
mr Goodwill [35]

The number of those who attended the picnic was 8.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.

Such questions are best examples of quadratic equations where  the unknown is simply assumed to be a variable which when substituted according to the conditions yield a quadratic equation which can easily be solved.

Let x represent the whole population.

Total Spending = Rs. 96

Thus, each individual's contribution is equal to 96/x.

Four people did not show up causing

others to contribute Rs. 4 extra.

So the given condition can be written as

96/(x-4) – 96/x = 4

=>96x – 96(x-4) = 4x(x-4)

=> 96x -96x + 384 = 4x2 – 16x

=> 4x2 – 16x – 384 = 0

=> x2 – 4x – 96 = 0

=> (x – 12)(x + 8) = 0

=> x = 12 or x = -8 (neglect)

So x = 12

x-4 = 8  ( because  four of them did not turn up)

∴ The number of those who attended the picnic was 8.

Learn more about quadratic equations here :

brainly.com/question/15241362

#SPJ4

4 0
2 years ago
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