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s344n2d4d5 [400]
2 years ago
6

the radio of used cars at a dealership is 7:5. if the dealership has 156 cars on the lot , how many are new ?​

Mathematics
1 answer:
Serggg [28]2 years ago
3 0

Answer:

91 used

65 new

Step-by-step explanation:

7 + 5 = 12

156/12 = 13

7(13) = 91

5(13) = 65

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at a shop on times square three''I love NY'' shirts sell every 10 minutes for $19.95 each.Every 45 minutes on Yankee's hat sells
Marizza181 [45]
I believe the answer 30,164.4
 
you multiply 19.95 by 3 and you get 59.85
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5 0
2 years ago
PLEASE HELP ME PLEASE
Rama09 [41]

Answer:

Option B. 3/4 > 2/3 is the correct answer.

Step-by-step explanation:

Lets look at the options one by one

A. 1/2 < 1/3

This inequality converts into 0.5<0.33 which is false.

B. 3/4 > 2/3

This simplifies to 0.75>0.666 which is true.

C. -1/4 < - 2/3

This converts to -0.25<-0.666 which makes the inequality false.

D. -1 > 3/4​

This converts to -1>0.75 which makes the inequality false.

Hence,

Option B. 3/4 > 2/3 is the correct answer.

5 0
3 years ago
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I don't know the answer to this and I've been stuck on it for a while now. Please can someone answer this
Natasha_Volkova [10]
Multiply each term by 8 ( to get rid of the fractions) 
we get:-
-72 = -16 - k

k = -16 + 72 = 56 answer
8 0
2 years ago
Please answer these questions for me I wanna enjoy being outside today.
Arlecino [84]

Answer:

1. y = 3x - 3

2. y = -2 1/2x + 10

10/-4 = -2 1/2 is the slope

3.  undefined

4. y = x - 4

5. y = x - 5

6. 6x + 2y = 4 and -3y = 9x + 12

7. -3x + y = 7, y = 3x + 1, and y =3x

8. y = 2x + 5

9. y = 1/4x - 4

4 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
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