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Arisa [49]
3 years ago
6

Text Jim Belushi Lanka Lanka ​

Mathematics
1 answer:
mestny [16]3 years ago
3 0

Answer:

26.a

27 c

28.a

Step-by-step explanation:

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3 years ago
Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]

The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.

<h3>How to determine the range of a function?</h3>

Given: 12x + 6y = 24

Here x stands for the input and y stands for the output

Replacing y with f(x)

12x + 6f(x) = 24

6f(x) = 24 - 12x

f(x) = (24 - 12x)/6

Domain = {-4, 0, 5}

Put the elements of the domain, one by one, to estimate the range

f(-4) = (24 - 12((-4))/6

= (72)/6 = 12

f(0) = (24 - 12(0)/6

= (24)/6 = 4

f(5) = (24 - 12(5)/6

= (-36)/6 = -6

The range exists {12, 4, -6}

Therefore, the correct answer is option c. {12, 4, -6}.

To learn more about Range, Domain and functions refer to:

brainly.com/question/1942755

#SPJ4

7 0
2 years ago
Match the circle equations in general form with their corresponding equations in standard form. x2 y2 − 4x 12y − 20 = 0 (x − 6)2
frosja888 [35]

The equation given is matched with the respective vertex forms.

<h3>What is the standard Equation for a circle ?</h3>

The standard equation for a circle is given by

(x-h)² + (y-k)² = r²

The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

5x²  + 5y²  − 10x + 20y − 30 = 0

(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

(x+3)²  + (y-4)²  = 35

The third equation is

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

The fourth equation is

5x²  + 5y²  − 10x + 20y − 30 = 0

(x-1)²  + (y+2)²   = 11

The fifth equation is

2x²  + 2y²  − 24x − 16y − 8 = 0

(x − 6)²  + (y − 4)²  = 56

To know more about standard equation of Circle

brainly.com/question/13658927

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7 0
2 years ago
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