![Our \ goal \ here\ is \ to \ find \ an \ acid-base \ conjugate \ pair \ that \ have \a \\\$pK_a-p H$. This is because we assume that the acid-base conjugate pair have an equal concentration to be considered an effective buffer.](https://tex.z-dn.net/?f=Our%20%5C%20goal%20%5C%20here%5C%20%20is%20%5C%20to%20%5C%20find%20%5C%20an%20%5C%20acid-base%20%5C%20conjugate%20%5C%20pair%20%5C%20that%20%5C%20have%20%5Ca%20%5C%5C%5C%24pK_a-p%20H%24.%20This%20is%20because%20we%20assume%20that%20the%20acid-base%20conjugate%20pair%20have%20an%20equal%20concentration%20to%20be%20considered%20an%20effective%20buffer.)
![$$p H-p K_a+\log \frac{\left[A^{-}\right]}{[H A]}$$](https://tex.z-dn.net/?f=%24%24p%20H-p%20K_a%2B%5Clog%20%5Cfrac%7B%5Cleft%5BA%5E%7B-%7D%5Cright%5D%7D%7B%5BH%20A%5D%7D%24%24)
![$$Where $\left[A^{-}\right]-[H A]$, so $\log \frac{\left[A^{-}\right]}{[H A]}-\log 1-0_{\text {so ... }}$$$](https://tex.z-dn.net/?f=%24%24Where%20%24%5Cleft%5BA%5E%7B-%7D%5Cright%5D-%5BH%20A%5D%24%2C%20so%20%24%5Clog%20%5Cfrac%7B%5Cleft%5BA%5E%7B-%7D%5Cright%5D%7D%7B%5BH%20A%5D%7D-%5Clog%201-0_%7B%5Ctext%20%7Bso%20...%20%7D%7D%24%24%24)
pH-pKa
![$$Solve for $K_a$.$$](https://tex.z-dn.net/?f=%24%24Solve%20for%20%24K_a%24.%24%24)
![$$\begin{aligned}p H-p K_a &--\log K_a \\K_a &-10^{-p H} \\&-10^{-3.5} \\K_a &-3.2 \times 10^{-4}\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7Dp%20H-p%20K_a%20%26--%5Clog%20K_a%20%5C%5CK_a%20%26-10%5E%7B-p%20H%7D%20%5C%5C%26-10%5E%7B-3.5%7D%20%5C%5CK_a%20%26-3.2%20%5Ctimes%2010%5E%7B-4%7D%5Cend%7Baligned%7D%24%24)
![$$The nearest pairs are $\mathrm{HCOCOOH} / \mathrm{HCOCOO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-3.5 \times 10^{-4}$,](https://tex.z-dn.net/?f=%24%24The%20nearest%20pairs%20are%20%24%5Cmathrm%7BHCOCOOH%7D%20%2F%20%5Cmathrm%7BHCOCOO%7D%5E%7B-%7D%24with%20a%20%24%5Cmathrm%7BK%7D_%7B%5Cmathrm%7Ba%7D%7D-3.5%20%5Ctimes%2010%5E%7B-4%7D%24%2C)
![$\mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COOH} / \mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-2.9 \times 10^{-4}$, and](https://tex.z-dn.net/?f=%24%5Cmathrm%7BHOCH%7D_2%20%5Cmathrm%7BCH%7D%28%5Cmathrm%7BOH%7D%29%20%5Cmathrm%7BCOOH%7D%20%2F%20%5Cmathrm%7BHOCH%7D_2%20%5Cmathrm%7BCH%7D%28%5Cmathrm%7BOH%7D%29%20%5Cmathrm%7BCOO%7D%5E%7B-%7D%24with%20a%20%24%5Cmathrm%7BK%7D_%7B%5Cmathrm%7Ba%7D%7D-2.9%20%5Ctimes%2010%5E%7B-4%7D%24%2C%20and)
![$\mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COOH} / \mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COO}^{-}$with a $\mathrm{K}_a-3.6 \times 10^{-4}$. We can also check for the $\mathrm{K}_b$. First, solve for $p K_b$ then the $K_b$ -](https://tex.z-dn.net/?f=%24%5Cmathrm%7BCH%7D_3%20%5Cmathrm%7BCOOC%7D_6%20%5Cmathrm%7BH%7D_4%20%5Cmathrm%7BCOOH%7D%20%2F%20%5Cmathrm%7BCH%7D_3%20%5Cmathrm%7BCOOC%7D_6%20%5Cmathrm%7BH%7D_4%20%5Cmathrm%7BCOO%7D%5E%7B-%7D%24with%20a%20%24%5Cmathrm%7BK%7D_a-3.6%20%5Ctimes%2010%5E%7B-4%7D%24.%20We%20can%20also%20check%20for%20the%20%24%5Cmathrm%7BK%7D_b%24.%20First%2C%20solve%20for%20%24p%20K_b%24%20then%20the%20%24K_b%24%20-)
![$$\begin{aligned}p K_w &-p K_b+p K_a \\p K_b &-p K_w-p K_a \\&-14-3.5 \\p K_b &-10.5 \\p K_b &--\log K_b \\K_b &-10^{-p K_b} \\&-10^{-10.5} \\K_b &-3.2 \times 10^{-11}\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7Dp%20K_w%20%26-p%20K_b%2Bp%20K_a%20%5C%5Cp%20K_b%20%26-p%20K_w-p%20K_a%20%5C%5C%26-14-3.5%20%5C%5Cp%20K_b%20%26-10.5%20%5C%5Cp%20K_b%20%26--%5Clog%20K_b%20%5C%5CK_b%20%26-10%5E%7B-p%20K_b%7D%20%5C%5C%26-10%5E%7B-10.5%7D%20%5C%5CK_b%20%26-3.2%20%5Ctimes%2010%5E%7B-11%7D%5Cend%7Baligned%7D%24%24)
![There \ are\ no \ pairs \ near \ this \ $K_b$ value.](https://tex.z-dn.net/?f=There%20%5C%20are%5C%20%20no%20%5C%20pairs%20%5C%20near%20%5C%20%20this%20%5C%20%20%24K_b%24%20value.)
<h3>What is a conjugate acid and base pair?</h3>
An acid-base pair that differs by one proton is referred to as a conjugate pair. A conjugate acid-base pair is a pair of substances that can both absorb and donate hydrogen ions to one another. A proton is added to the compound to create the conjugate acid, and a proton is taken out to create the conjugate base. When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created.
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brainly.com/question/10468518
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Answer:
hopefully this helps some
Answer:
A = l×b
Explanation:
Rectangle is a closed figure with 4 vertices. Each angle of a rectangle is 90 degrees. The opposite sides of a rectangle are equal.
Let l is the length of opposite sides of a rectangle and b is the breadth of the opposite sides of a rectangle.
The area of a rectangle is then given by :
A = l×b
i.e. area of a rectangle is equal to length times breadth.
Answer:
<em>Making observation</em>
Explanation: