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Lesechka [4]
3 years ago
6

How are ions formed? by the disintegration of one or more electrons by the sharing of one or more electrons between two atoms by

the transfer of one or more electrons from one atom to another by the disintegration of one or more protons
Chemistry
2 answers:
LiRa [457]3 years ago
8 0

<u>Answer:</u> The correct answer is by the transfer of one or more electrons from one atom to another.

<u>Explanation:</u>

Ions are the charged species that are formed when electrons get added up or are lost from an atom.

If an atom looses electrons, it will lead to the formation of positively charged ion known as cation.

If an atom gains electrons, it will lead to the formation of negatively charged ion known as anion.

Ions are also formed when an atom transfers its electrons to another atom. In this way, the atom which is donating electron will attain positive charge and the ion which is accepting electrons, will attain negative charge.

Thus, the correct answer is by the transfer of one or more electrons from one atom to another.

Debora [2.8K]3 years ago
6 0
By the transfer of one or more electrons from one atom to another

for example,
2Na + Cl₂ → 2Na⁺Cl⁻

Na - e⁻ → Na⁺
Cl₂ + 2e⁻ → 2Cl⁻
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Answer:

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3 years ago
Calculate the enthalpy change, ∆H in kJ, for the reaction H2O(s) → H2(g) + 1/2O2(g). Use the following information: : +279.9 kJ
Len [333]

Answer:

+ 291.9 kJ

Solution:

The equation given is as;

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = ?

First, as we know the heat of formation of H₂O ₍l₎ is,

H₂ ₍g₎ + 1/2 O₂ ₍g₎ → H₂O ₍l₎ ΔH = - 285.9 kJ

Now, reversing the equation will reverse the sign of heat as,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

Also, we know that,

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

Now, adding last two equations,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

-----------------------------------------------------------------------------

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 291.9 kJ

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Balanced equation with corresponding stoichiometric numbers.

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