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Lesechka [4]
3 years ago
6

How are ions formed? by the disintegration of one or more electrons by the sharing of one or more electrons between two atoms by

the transfer of one or more electrons from one atom to another by the disintegration of one or more protons
Chemistry
2 answers:
LiRa [457]3 years ago
8 0

<u>Answer:</u> The correct answer is by the transfer of one or more electrons from one atom to another.

<u>Explanation:</u>

Ions are the charged species that are formed when electrons get added up or are lost from an atom.

If an atom looses electrons, it will lead to the formation of positively charged ion known as cation.

If an atom gains electrons, it will lead to the formation of negatively charged ion known as anion.

Ions are also formed when an atom transfers its electrons to another atom. In this way, the atom which is donating electron will attain positive charge and the ion which is accepting electrons, will attain negative charge.

Thus, the correct answer is by the transfer of one or more electrons from one atom to another.

Debora [2.8K]3 years ago
6 0
By the transfer of one or more electrons from one atom to another

for example,
2Na + Cl₂ → 2Na⁺Cl⁻

Na - e⁻ → Na⁺
Cl₂ + 2e⁻ → 2Cl⁻
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What is the modren system of classificationis based on
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3 years ago
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
Given the unbalanced equation: PbCl₂ + Na₂CrO₂ ---&gt; PbCrO₂ + NaCl. When properly balanced, the sum of the balancing coefficie
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Answer:

A. 2

hope this helps :)

if you need an explanation let me know!!

3 0
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