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Lesechka [4]
3 years ago
6

How are ions formed? by the disintegration of one or more electrons by the sharing of one or more electrons between two atoms by

the transfer of one or more electrons from one atom to another by the disintegration of one or more protons
Chemistry
2 answers:
LiRa [457]3 years ago
8 0

<u>Answer:</u> The correct answer is by the transfer of one or more electrons from one atom to another.

<u>Explanation:</u>

Ions are the charged species that are formed when electrons get added up or are lost from an atom.

If an atom looses electrons, it will lead to the formation of positively charged ion known as cation.

If an atom gains electrons, it will lead to the formation of negatively charged ion known as anion.

Ions are also formed when an atom transfers its electrons to another atom. In this way, the atom which is donating electron will attain positive charge and the ion which is accepting electrons, will attain negative charge.

Thus, the correct answer is by the transfer of one or more electrons from one atom to another.

Debora [2.8K]3 years ago
6 0
By the transfer of one or more electrons from one atom to another

for example,
2Na + Cl₂ → 2Na⁺Cl⁻

Na - e⁻ → Na⁺
Cl₂ + 2e⁻ → 2Cl⁻
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Why is peer review an Important part of the scientific process
guajiro [1.7K]
Peer review involves subjecting the author's scholarly work and research to the scrutiny of other experts in the same field to check its validity and evaluate its suitability for publication. A peer review helps the publisher decide whether a work should be accepted.
7 0
3 years ago
Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.
il63 [147K]

Answer is: the ratio of the effusion rate is 1.59 : 1.

1) rate of effusion of carbon monoxide gas = 1/√M(CO).  

rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.  

2) rate of effusion of chlorine = 1/√M(Cl₂).  

rate of effusion of chlorine = 1/√70.9.  

rate of effusion of chlorine = 0.119.  

rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

4 0
3 years ago
How many grams are in 4.07x10^15 molecules of calcium hydroxide
maksim [4K]

There are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molecular mass.

However, given that the number of molecules in calcium hydroxide is 4.07 x 10¹⁵molecules, we need to calculate the number of moles in Ca(OH)2 as follows:

no. of moles of Ca(OH)2 = 4.07 x 10¹⁵ ÷ 6.02 × 10²³

no. of moles = 0.676 × 10-⁸

no. of moles = 6.76 × 10-⁹ moles.

Molar mass of Ca(OH)2 = 74.093 g/mol

Mass of Ca(OH)2 = 74.093 × 6.76 × 10-⁹ moles

Mass = 5.01 × 10-⁷grams.

Therefore, there are 5.01 × 10-⁷grams in 4.07 x 10¹⁵molecules of calcium hydroxide.

Learn more about how to calculate mass at: brainly.com/question/8101390?referrer=searchResults

5 0
2 years ago
What is the oxidation number of s in na2s4o6?
Novosadov [1.4K]

Answer:

+2.5

Explanation:

So the oxidation number of S in Na2S4O6is +2.5.

7 0
3 years ago
Read 2 more answers
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
Zolol [24]

This is an incomplete question, here is a complete question.

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.15\times 10^6m/s?

Find the force acting on the electron as it revolves in a circular orbit of radius 5.34\times 10^{-11}m.

Answer : The force acting on electron is, 7.9\times 10^{-8}N

Explanation :

Formula used :

F=\frac{mv^2}{r}

where,

F = force acting on electrons

m = mass of electrons = 9.1\times 10^{-31}kg

v = speed of electron = 2.15\times 10^6m/s

r = radius of circular orbit = 5.34\times 10^{-11}m

Now put all the given values in the above formula, we get:

F=\frac{(9.1\times 10^{-31}kg)\times (2.15\times 10^6m/s)^2}{5.34\times 10^{-11}m}

F=7.9\times 10^{-8}N

Thus, the force acting on electron is, 7.9\times 10^{-8}N

8 0
3 years ago
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