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3 years ago

PLEASE HELP FAST!!!!

1 answer:

7 0

2C + O2 = 2CO is balanced.

If you look you can see the first side has 2 Cs and 2 Os, and the other side has the same amount, just put together making both sides even and balanced.

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Are you sure it’s d<br> Plz tell me

Virty [35]

Answer:

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Explanation:

8 0

2 years ago

Would a false positive from the reaction between the inoculating loop and hydrogen peroxide

Svetradugi [14.3K]

The false positive from the response of hydrogen peroxide and the immunizing circle would be created by poor specificity. The recipe for specificity is TN/TN+FP. False-positive outcomes can be ascribed to meddling substances in nature where the strips are put away or utilized, for example, hydrogen peroxide (H2O2) or fade (hypochlorite).

3 0

3 years ago

What is chemical nitrogen

Alika [10]

Nitrogen is the chemical element with the symbol N and atomic number 7. ... At standard temperature and pressure, a colourless and odorless atomic gas with the formula N. nitrogen forms about 78% of Earth's atmosphere.

4 0

2 years ago

Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At 16°

Pavel [41]

Answer:

PNO₂ = 0.49 atm

PN₂O₄ = 0.45 atm

Explanation:

Let's begin with the equation of ideal gas, and derivate from it an equation that involves the density (ρ = m/V).

PV = nRT

n = m/M (m is the mass, and M the molar mass)

$PV = \frac{m}{M}RT$

$PxM = \frac{m}{V}RT$

PxM = ρRT

ρ = PxM/RT

With the density of the gas mixture, we can calculate the average of molar mass (Mavg), with the constant of the gases R = 0.082 atm.L/mol.K, and T = 16 + 273 = 289 K

$2.7 = \frac{0.94xMavg}{0.082x289}$

0.94Mavg = 63.9846

Mavg = 68.0687 g/mol

The molar mass of N is 14 g/mol and of O is 16 g/mol, than $M_{NO2} = 46$ g/mol and $M_{N2O4} = 96$ g/mol. Calling y the molar fraction:

$Mavg = M_{NO2}y_{NO2} + M_{N2O4}y_{N2O4}$

And,

$y_{NO2} + y_{N2O4} = 1$

$y_{N2O4} = 1 - y_{NO2}$

So,

$68.0687 = 46y_{NO2} + 92x(1 - y_{NO2})$

$68.0687 - 92 = 46y_{NO2} - 92y_{NO2}$

$46y_{NO2} = 23.9313$

$y_{NO2} = 0.52$

$y_{N2O4} = 0.48$

The partial pressure is the molar fraction multiplied by the total pressure so:

PNO₂ = 0.52x0.94 = 0.49 atm

PN₂O₄ = 0.48x0.94 = 0.45 atm

8 0

3 years ago

Mg + 2 AgNO₃ → Mg(NO₃)₂ + 2 Ag How many grams of magnesium nitrate, Mg(NO₃)₂, are formed when 9.87 moles of silver nitrate, AgNO

Aleksandr-060686 [28]

Mass of Magnesium nitrate formed : 731.86 g

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

Mg + 2AgNO₃ → Mg(NO₃)₂ + 2 Ag

moles of silver nitrate, AgNO₃ = 9.87

mole ratio AgNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :

$\tt \dfrac{1}{2}\times 9.87=4.935$

mass of Mg(NO₃)₂(MW=148,3 g/mol) :

$\tt mass=mol\times MW\\\\mass=4.935\times 148,3\\\\mass=731.86~g$

4 0

2 years ago