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tatuchka [14]
4 years ago
12

Write the electron dot structures for the following elements:

Chemistry
1 answer:
Evgesh-ka [11]4 years ago
7 0

Answer:

Drawings of Lewis structure Are attached for your elements

Explanation:

Please open the attachment

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Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .
Nimfa-mama [501]

Answer:

\Delta H=-28.08 \frac{kJ}{mol}

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}

Which accounts for an exothermic chemical reaction.

Regards.

7 0
4 years ago
How does frost form?
hram777 [196]

Answer:

Frost forms when an outside surface cools past the dew point.

Example: The dew point is the point where the air gets so cold, the water vapor in the atmosphere turns into liquid. This liquid freezes. If it gets cold enough, little bits of ice, or frost, form.

3 0
3 years ago
Read 2 more answers
1.
guajiro [1.7K]

Answer:

The flask would probably feel cooler than before the reaction started.

Reasoning:

Endothermic is a process or reaction accompanied by or requiring the absorption of heat

3 0
4 years ago
If you have 74.4 liters Argon what is the mass in grams
Sloan [31]
1 liter is 1000 grams so 74.4*1000=74400 grams
7 0
3 years ago
The standard enthalpy of combustion of naphthalene is –5157 kj mol-1. calculate its standard enthalpy of formation. (use data in
Artemon [7]

The combustion of naphthalene is given as:

C10H8 (s) + 12 O2 (g) --> 10CO2 (g) + 4 H2O (l)

Enthalpy of combustion ΔH = -5157 kJ/mol

Now, the enthalpy change of a reaction is given

ΔH = ∑nΔHf (products) - ∑nΔHf (reactants)

where n = number of moles

            ΔHf = enthalpy of formation

Therefore,

ΔH = [10*ΔHf(CO2) + 4*ΔHf(H2O)] - [1*ΔHf(C10H8) + 12*O2]

-5157 = [10*(-393.5) + 4*(285.83)] - [ΔHf(C10H8) + 12*(0)]

ΔHf(C10H8) = 78.68 kJ/mol

4 0
4 years ago
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