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tatuchka [14]
4 years ago
12

Write the electron dot structures for the following elements:

Chemistry
1 answer:
Evgesh-ka [11]4 years ago
7 0

Answer:

Drawings of Lewis structure Are attached for your elements

Explanation:

Please open the attachment

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Answer:

2,137... gallons

Explanation:

(160+140+14x16x2)/350=2,137...

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Calculate the specific heat for as air if 1500.0 joules are required to raise the temperature of 50.0g from 0.0c to 40.0c
Law Incorporation [45]

The specific heat, c is 0.75 J/g°C

<u>Explanation:</u>

Heat or Energy, Q = 1500J

Mass, m = 50g

T1 =  0°C

T2 = 40°C

Specific Heat, c = ?

We know,

Q = mcΔT

Q = mc(T2-T1)

1500 = 50 X c X (40-0)

1500 = 50 X c X 40

c = 1500/ 2000

c = 0.75 J/g°C

Therefore, the specific heat, c is 0.75 J/g°C

7 0
3 years ago
A 1.000 g sample of an unknown hydrate of cobalt chloride is gently dehydrated. The resulting mass is 0.546 g. The cobalt is iso
ira [324]

Answer:

Explanation:

From the 1 g sample you have:

0.546 grams of cobalt chloride

1-0.546=0.454 grams of water

Now:

1) The salt

Of the 0.546 g, 0.248 g are cobalt (Mr=58.9) and the rest id Cl (Mr=35.45):

n_{Co}=\frac{0.248 g}{58.9 g/mol}=4.21*10^{-3}mol

n_{Cl}=\frac{0.298 g}{35.45g/mol}=8.4*10^{-3}mol

Dividing:

\frac{n_{Cl}}{n_{Co}}=\frac{8.4*10^{-3}mol}{4.21*10^{-3}mol}=2

So the molecular formula will be:

CoCl_2

2) The water

The water's molecular weight is M=18 :

n_{w}=\frac{0.454g}{18g/mol}=0.025 mol

Bonding with the Co:

\frac{n_{w}}{n_{Co}}=\frac{0.025mol}{4.21*10^{-3}mol}=6

The complete formula of the hydrate:

CoCl_2*6 H_2O

8 0
4 years ago
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