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Elena-2011 [213]
2 years ago
8

20 points, pls help, its angles​

Mathematics
1 answer:
Zina [86]2 years ago
3 0
Okay what’s the question
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If an item weighs 45 kilograms, what is its weight in pounds?
In-s [12.5K]
1 kilogram = 2.2 pounds
45 kilograms = 2.2 x 45 = 99 pounds
5 0
3 years ago
Mr berry has $500 in a savings account at the beginning of the summer. He wants to have at least $200 in the account by the end
vampirchik [111]

Answer:

500$=tension(x)-200$-25$week

6 0
3 years ago
Anita sees in her nutrition book that a 7.5-ounce piece of cake has 900 calories. how many calories will she save if she takes o
Marianna [84]
\bf \begin{array}{ccll}
\stackrel{cake}{oz}&calories\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
7.5&900\\
2.5&x
\end{array}\implies \cfrac{7.5}{2.5}=\cfrac{900}{x}\implies x=\cfrac{2.5\cdot 900}{7.5}

so, the 2.5oz cake will be "x" calories, pheeew, she'll be taking in 900 - x less calories.
8 0
3 years ago
If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?
Diano4ka-milaya [45]

Answer:

x=8

\m\angle HFG= 80^\circ

Step-by-step explanation:

Given that:

Point H is interior of \angle EFG.

m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ

To find:

x = ?\\m\angle HFG = ?

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

m\angle EFG = m\angle EFH + m\angle HFG

Putting all the values given in above equation, we get:

(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}

m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}

8 0
3 years ago
Can someone please help me and ill mark you as brainlest
Vitek1552 [10]

9514 1404 393

Answer:

  F.  30·tan(52°)

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship between the opposite and adjacent sides in a right triangle.

  Tan = Opposite/Adjacent

  tan(52°) = BD/DL

  BD = DL·tan(52°)

The boat-to-dock distance is ...

  30·tan(52°) . . . . matches F

6 0
3 years ago
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