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bixtya [17]
3 years ago
6

I ONLY GIVE CROWN TO ANSWERS THAT ARE CORRECT THANK YOU VERY MUCH :)

Mathematics
1 answer:
lana [24]3 years ago
3 0

Answer:

260

Step-by-step explanation:

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Heather purchased a new $1,500 laptop by using a credit card with a 17% interest rate. She will pay off the balance in 2 years b
olga2289 [7]

Answer:

1779.84

Step-by-step explanation:

7 0
3 years ago
What fraction is the greatest in this row? 12/4, 4/4, 2 2 / 4, 1/4. also 2 2 /4 is a mixed number
kakasveta [241]

Answer:

12/4

Step-by-step explanation:

4/4 is 1

1/4 is well 1/4

2 2/4 is 2 1/2

12/4 is 3

the greatest fraction is 3

4 0
3 years ago
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Solve the radical equation.<br> sqrt 25 – 40x = X – 10
Citrus2011 [14]

-40x=-10-20

-40x=-35

x= 7/8

5 0
2 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
Aaron, Blaine, and Cruz are solving the equation
stiv31 [10]

Answer:

All three chose a valid first step toward solving the equation.

All approaches are algebraically correct

7 0
3 years ago
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