Question

The amount of work required to increase the distance between -6μC and 4μC from 6 cm to 18 cm will be

Answer 1

Answer:

W = 1.8 J

Explanation:

The amount of work required to move the given charges can be found by using the following formula:

$W = \frac{kq_1q_2}{\Delta r}$

where,

W = Work done = ?

k = Colomb's constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ C

q₂ = magnitude of second charge = 4 μC = 4 x 10⁻⁶ C

Δr = change in distance = 18 cm - 6 cm = 12 cm = 0.12 m

Therefore,

$W = \frac{(9\ x\ 10^9\ Nm^2/C^2)(6\ x\ 10^{-6}\ C)(4\ x\ 10^{-6}\ C)}{0.12\ m}$

W = 1.8 J