Answer:Problem 1 – The entire International Space Station orbits Earth at a speed of 28,000 kilometers per hour (17,000 mph). At this speed, how many days
Explanation:
Answer:
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Explanation:
Responder:
<h2>
0.7Hertz
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Explicación:
Usando la fórmula para calcular la velocidad de onda que se expresa como se muestra.
Velocidad de una onda = frecuencia * longitud de onda
v = fλ
Dada la velocidad de onda = 14 m / sy longitud de onda = 20 metros
frecuencia f = v / λ
f = 14/20
f = 0.7Hertz
La frecuencia de la onda es de 0.7 Hertz.
Trigonometry allows finding the result for the decomposition of the displacement vector is:
x = 2.12 mi
y = -2.12 mi
Displacement is a vector quantity, which has modulus and direction.
The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.
In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:
θ = 360 - 45
θ = 315º
Let's use trigonometry to decompose the vector d = 3 mi
cos 315 =
sin 315 =
x = d cos 315
y = d sin 315
Let's calculate
x = 3 cos 315
y = 3 sin 315
x = 2.12 mi
y = -2.12 mi
The negative sign indicates that the displacement is towards the negative side, that is, towards the South.
In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:
x = 2.12 mi
y = -2.12 mi
Learn more here: brainly.com/question/1666179
Answer:
The De Broglie wavelength decreases
Explanation:
The relationship between the De Broglie wavelength of a particle and its momentum is given by
where
is the De Broglie wavelength of the particle
h is the Planck constant
p is the momentum of the particle
As we see from the formula, there is an inverse relationship between the De Broglie's wavelength and the momentum. Therefore, we can conclude that:
- if the momentum of the electron increases,
- its De Broglie wavelength will decrease
and vice-versa.