A 1500 kg car accelerates at 3 m/s^2. What is the net force acting on the car?
1 answer:
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Answer:
acceleration is 9.58 × (- 14 ĵ + 51 k ) m/s
Explanation:
given data
uniform electric field E = 54.0 ĵ V/m
uniform magnetic field B = (0.200 î + 0.300 ĵ + 0.400 k) T
velocity v = 170 î m/s.
to find out
acceleration
solution
we know magnetic force for proton is
i.e = e (velocity × uniform magnetic field)
magnetic force = e (170 î × (0.200 î + 0.300 ĵ + 0.400 k) )
magnetic force = e (- 68 ĵ + 51 k ) ..................1
and now for electric force for proton i.e
= uniform electric field × e ĵ
electric force = e (54 ĵ ) ............2
so net force will be add magnetic force + electric force
from equation 1 and 2
e (- 68 ĵ + 51 k ) + e (54 ĵ )
e (- 14 ĵ + 51 k )
so the acceleration (a) for proton will be
net force = mass × acceleration
a = e (- 14 ĵ + 51 k ) / 1.6 / 1.67 ×
acceleration = 9.58 × (- 14 ĵ + 51 k ) m/s