Answer:
120
Step-by-step explanation:
That's a guess, but it's the most logical one.
Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
He will use 33 containers because 9 goes into 296 32.8 times but you cant have .8 of a container so you round it up to 33
Answer:
c) (8^6) / 8 = 32768
d) (7^8) / (7^6) = 49
Step-by-step explanation:
Answer:
Explanation:
Identity: sec2θ=1+tan2θ
sec2(π2−x)−1=1+tan2(π2−x)−1
=tan2(π2−x)
Identity: tan(π2−θ)=cotθ
=cot2x
