You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.
6 • 52 = 312
He could potentially take 312 lessons in one year.
Now that you know this information, you simply subtract the days he missed from that total.
312 - 5 = 307
Your final answer: Peter took 307 lessons during the year.
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
c=
−4
3
s−t+
−4
3
Step-by-step explanation:
Let's solve for c.
3s+2t−3c−7s−5t=4
Step 1: Add 4s to both sides.
−3c−4s−3t+4s=4+4s
−3c−3t=4s+4
Step 2: Add 3t to both sides.
−3c−3t+3t=4s+4+3t
−3c=4s+3t+4
Step 3: Divide both sides by -3.
−3c
−3
=
4s+3t+4
−3
c=
−4
3
s−t+
−4
3
