Answer:
I believe the answer is C.
Step-by-step explanation:
brainliest?? if correct
I assume you need to solve for g?
12g + 6 = 78
- 6
12g = 72
÷ 12
g = 6
I hope this helps! Let me know if you want me to explain anything :)
False.it could be any they all have atleast a 15% chance of it being a number that’s 1-6.
Answer:
Step-by-step explanation:
Consider first
![y_1(t) = t^2\\](https://tex.z-dn.net/?f=y_1%28t%29%20%3D%20t%5E2%5C%5C)
We differentiate this two times to get
![y_1'(t) = 2t\\y_1"(t) =2](https://tex.z-dn.net/?f=y_1%27%28t%29%20%3D%202t%5C%5Cy_1%22%28t%29%20%3D2)
Substitute in the given equation
![t^2 (2) -2(t^2 =0](https://tex.z-dn.net/?f=t%5E2%20%282%29%20-2%28t%5E2%20%3D0)
Hence satisfied
Consider II equation
![y_2(t) = t^{-1} \\y_2'(t) = - t^{-2}\\y_2"(t) = -2 t^{-3}](https://tex.z-dn.net/?f=y_2%28t%29%20%3D%20t%5E%7B-1%7D%20%5C%5Cy_2%27%28t%29%20%3D%20-%20t%5E%7B-2%7D%5C%5Cy_2%22%28t%29%20%3D%20-2%20t%5E%7B-3%7D)
Substitute in the given equation to get
![t^2 (-2 t^{-3})+2 t^{-1} = 0](https://tex.z-dn.net/?f=t%5E2%20%28-2%20t%5E%7B-3%7D%29%2B2%20t%5E%7B-1%7D%20%3D%200)
Hence satisfied
Together if we have
![y = c_1 t^2 +c_2 t^{-1}](https://tex.z-dn.net/?f=y%20%3D%20c_1%20t%5E2%20%2Bc_2%20%20t%5E%7B-1%7D)
being linear combination of two solutions
automatically this also will satisfiy the DE Or
this is a solution to the given DE