Ask question

Ask question

All categories

3 years ago

12

What is 3 1/3 *2/3?

2 answers:

Molodets [167]3 years ago

6 0

Answer:2 2/9

Step-by-step explanation:

3 1/3= 10/3, 10/3 x 2/3= 20/9= 2 2/9

Artyom0805 [142]3 years ago

3 0

Answer:

2.2222222

Step-by-step explanation:

Use a calculator

You might be interested in

Which method would be the best to solve the following system of equations? [5x + 3y = -7 -2x – 3y = 19]

ZanzabumX [31]

Your answer is (B) ;) i hope

4 0

3 years ago

Which function has zeros at x = 10 and x = 2? A f(x) = x2 – 12x + 20 B f(x) = x2 – 20x + 12 C f(x) = 5x2 + 40x + 60 D f(x) = 5x2

kow [346]

You have to set it up as two problems then combined like terms then add them together

8 0

3 years ago

Read 2 more answers

Select all systems of equations that have no solutions.

luda_lava [24]

Answer:

Step-by-step explanation:

bayak

8 0

3 years ago

Read 2 more answers

The location of an ant from a tree was 3 meters west (negative direction). The ant walked towards the tree at a constant rate an

nadya68 [22]

<span>y represents location, and it says the ant was 3 meters away in the negative direction to begin with. So, make sure the beginning of the line segment is at -3 on the y-axis. Next, it says to measure time in minutes with x, and it took the ant 2 minutes to get to the tree. So the end of the line segment would be at 2 on the x-axis</span>

4 0

4 years ago

Read 2 more answers

f(x) = 20(1.5)x. Let your dependent variable in the function be y. Write the function that models the independent variable in te

mars1129 [50]

Answer:

$x=log_{1.5}(\frac{y}{20})$

Step-by-step explanation:

Considering the function:

$f(x) = 20\, (1.5)^x$

The independent variable is "x" and we are asked to model it in terms of the variable "y":

$f(x) = 20\, (1.5)^x\\y=20\, (1.5)^x$

Then, in order to solve for x (which resides in the exponent), we need to use the logarithm function.

Since the base of the exponent is 1.5, we need to use the logarithm base 1.5, to lower that exponent "x":

$y=20\, (1.5)^x\\\frac{y}{20} =(1.5)^x\\log_{1.5}(\frac{y}{20}) =x\\x=log_{1.5}(\frac{y}{20})$

6 0

3 years ago