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Tanya [424]
3 years ago
9

5 is what percentage of 25? I’ll give brainliest:)

Mathematics
1 answer:
lord [1]3 years ago
3 0

Hi there! :)

<h2>20%</h2><h2></h2>

To solve, we can simply divide and multiply by 100 to solve for the percentage:

5 / 25     = 5 ÷ 25 = 1/5 or 0.20

Multiply the decimal by 100 to solve for the percentage:

0.20 × 100 = 20%

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Anybody know how to do this ?
pogonyaev

Hey there!

The interior angles of a triangle equal 180.

We can use this and the measures of the angles we are given to find the missing interior angle.

50+93=143

180-143=37

Since the missing angle (37) and angle x are supplementary, they add up to 180 as well.

37 + x = 180

180 - 37 = 143

x = 143

Hope this helps!

7 0
3 years ago
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3 years ago
Solve the system by substitution. <br> 7x-3y=-25 <br> 4x+5=y <br><br> Simplify<br> ( , )
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3 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
What is 10√94 simplified. Its not 98 or its decimal form.
slavikrds [6]

Answer:

hi

Step-by-step explanation:

i think 96(probably)

have a nice day

3 0
3 years ago
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