F(m) = 2.5 + 0.12m
if Natalie paid $6.82
6.82 = 2.5 + 0.12m
0.12m = 6.82 - 2.5
0.12m = 4.32
m = 4.32 ÷ 0.12
m = 36
The call was 36 minutes long.
(0,5)(4,0)
slope = (0 - 5) / (4 - 0) = -5/4
y = mx + b
slope(m) = -5/4
use either of ur sets of points....(0,5)...x = 0 and y = 5
now we sub and find b, the y int
5 = -5/4(0) + b
5 = b
so ur equation is : y = -5/4x + 5...but we need it in standard form...
y = -5/4x + 5
5/4x + y = 5....multiply everything by common denominator of 4
5x + 4y = 20 <== standard form of Ax + By = C
Answer:
![h(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
Step-by-step explanation:
we have
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
The inflection point of f(x) is the point 
The inflection point of h(x) is the point
-----> see the given graph
so
the rule of the translation of f(x) to h(x) is

That means------> The translation is
units to the left
therefore
The equation of h(x) is equal to
![h(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
Well, first, the equation that you are looking for is Y = MX + B. To find B, look at the first dot on the Y-axis. It starts at positive 3, so, you know your equation will end with +3. Next, to find MX, start at the either dot, and find the Rise/Run. In this particular equation, the rise is 1, and, the run is -2, because it's going backwards (negative line). Meaning, the line's equation would be, f( x )= -1/2x + 3.
Answer:
($2.123 ; $2.149)
Step-by-step explanation:
The prediction interval is expressed as :
Predicted value ± standard Error
Predicted value = $2.136
Standard Error = $0.013
Prediction interval :
Lower boundary = $2.136 - $0.013 = $2.123
Upper boundary = $2.136 + $0.013 = $2.149
($2.123 ; $2.149)
B.) The prediction interval provides a range for which the predicted value or price should fall Given a certain degree of probability. If the true value falls within this interval, then, our prediction would be deemed to have occurred not by chance.
Since the actual price within the predicted price interval, then I agree with the judge's Decison that the price was not artificially depressed.