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Mkey [24]
2 years ago
5

I need help fast if you help I will mark you as Brainlist

Mathematics
2 answers:
stira [4]2 years ago
4 0

Answer:

The answer is C

Step-by-step explanation:

Advocard [28]2 years ago
4 0

Answer:

42

Step-by-step explanation:

Garden 1.                        Garden 2

.    

.    

.    

3*7=21.                           3*7=21

21*2=42

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If f (x) = 5x + 4 then for what value of x will f(x) equal -11?​
uysha [10]

Answer:

-3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Ax+3=23 if a=0 plz help
VladimirAG [237]

Answer:

x = \frac{23}{a}

Step-by-step explanation:

Given equation is,

ax + 3 = 23

To solve this equation for the value of x isolate the variable 'x' on the one side of the equation.

Step 1,

Subtract 3 from both the sides of the equation.

ax + 3 - 3 = 23 - 3

ax = 20

Step 2,

Divide the equation by a,

\frac{ax}{a}=\frac{23}{a}

x = \frac{23}{a}

Therefore, x = \frac{23}{a} will be the answer.

6 0
3 years ago
Kurt says factors and multiples are
maxonik [38]

<u>Step-by-step Explanation:</u>

<em>Before heading towards the solution, you need to make sure how multiple and factors are related to each other.</em>

<em>The multiple of a number could be obtained by multiply it with another number. </em>

For example, the first five multiples of 12 are 12, 24, 36, 48 and 60

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36
  • 4 X 12 = 48
  • 5 X 12 = 60

<em>Factors are the numbers that are multiplied to get a given number.</em>

For example,

  • 1 X 12 = 12
  • 2 X 12 = 24
  • 3 X 12 = 36

The factors of 12 are 1, 2, 3, 4, 6 and 12.

As division and multiplication can be used to find factors and multiples.

For example a whole number is a multiple of its factors.

Let w = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20} be the set of even wholes numbers from 2 to 20.

As 2 is a factor of 20 because 20 ÷ 2 = 4

20 is a multiple of 2 because 2 X 10 = 20

So, in the same way, the equation 8 X 5 = 40 can be used to determine how factors and multiples are related.

Let the equation be

                                    8 X 5 = 40

8 is a factor of 40 because 8 X 5 = 40

40 is a multiple of 8 because 40 ÷ 5 = 8

<em>So, this is how factors and multiples are related to each other.</em>

<em />

<em>Keywords: factors, multiples, division, multiplication</em>

<em> Learn more about factors and multiples from brainly.com/question/596356</em>

<em> #learnwithBrainly</em>

4 0
2 years ago
The answer to this word problem usinf discriminant
solniwko [45]
\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2&#10;\\\\\\&#10;0=-9.8t^2+45t-63.3\\\\&#10;-------------------------------

\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}&#10;\\\\\\&#10;0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}&#10;~~~~~~&#10;\stackrel{discriminant}{b^2-4ac}=&#10;\begin{cases}&#10;0&\textit{one solution}\\&#10;positive&\textit{two solutions}\\&#10;negative&\textit{no solution}&#10;\end{cases}&#10;\\\\\\&#10;(45)^2-4(-9.8)(-63.3)\implies -456.36

the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.
8 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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