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Strike441 [17]
3 years ago
7

A function y = g(x) is graphed below. What is the solution to the equation g(x) = 3? x = 3 3 < x < 5 3 ≤ x ≤ 4 3 ≤ x <

5

Mathematics
1 answer:
Fittoniya [83]3 years ago
8 0

The Answer is:  x = 3

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How do u do this? HELPPPPPPPPPPPPPP
givi [52]
Bare with me a minute, I am still trying to figure it out. Here is what I have so far.

6 0
3 years ago
Write an equation in slope-intercept form for the following line:<br><br> (-14,1) and (13,-2)
alex41 [277]

Answer:

\large \boxed{y =  -  \frac{1}{9} x -  \frac{5}{9} }

Step-by-step explanation:

In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term is defined as slope in y = mx+b form which is slope-intercept form.

Now we substitute these ordered pairs (x, y) in the formula.

\large{m =  \frac{1 - ( - 2)}{ -14 - 13} } \\  \large{m =  \frac{1 + 2}{ - 27} } \\  \large{m =  \frac{3}{ - 27}  =  -  \frac{1}{9} }

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

\large \boxed{y = mx + b}

We already know m-value as we substitute it.

\large{y =  -  \frac{1}{9} x  + b}

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)

We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

\large{y = -  \frac{1}{9} x + b} \\  \large{ - 2 =  -  \frac{1}{9} (13) + b} \\  \large{ - 2 =  -  \frac{13}{9}  + b} \\  \large{ - 2 +  \frac{13}{9}  = b} \\  \large{ -  \frac{5}{9}  = b}

Finally, we know b-value. Then we substitute it in our equation.

\large{y =  -  \frac{1}{9} x + b} \\  \large{y =  -  \frac{1}{9} x -  \frac{5}{9} }

4 0
2 years ago
Simplify the expression csc(-x)/1+tan^2x)
Charra [1.4K]
Assuming ya meant \frac{csc(-x)}{1+tan^2(x)}

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos


for the pythaogreaon identity
cos^2(x)+sin^2(x)=1
divide both sides by cos^2(x)
1+tan^2(x)=sec^2(x) since \frac{sin(x)}{cos(x)}=tan(x)
subsitute
\frac{csc(x)}{sec^2(x)}

recall that csc(x)=\frac{1}{cos(x)}
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)
so we get

\frac{csc(x)}{sec^2(x)}
decompose them into \frac{1}{cos(x)} and \frac{1}{sin^2(x)} to get \frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}
multiply by \frac{sin^2(x)}{sin^2(x)} to get
\frac{sin^2(x)}{cos(x)}
we can furthur simlify to get
(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)
the expression simplifies to tan(x)sin(x)
5 0
3 years ago
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Answer: D) Adding heat to the reaction

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Which equation describes the relationship between the values in the table?
Sauron [17]

Answer: i think option 2

Step-by-step explanation: sorry if i get it wrong i try my best

7 0
3 years ago
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