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3 years ago

I need help with this pleaseee!!

Mathematics

2 answers:

Mrrafil [7]3 years ago

5 0

Yes

The definition Khan Academy gave is "A statistical question is one that can be answered by collecting data and where there will be variability in that data. For example, there will likely be variability in the data collected to answer the question, "How much do the animals at Fancy Farm weigh?" but not to answer, "What color hat is Sara wearing?".

A-C all don't have variability. They are set in place. However, the ages of all people in your class can change annd thus exhibit variability.

soldi70 [24.7K]3 years ago

3 0

A. No
B. No
C. Yes(probably)
D. Yes
(Sorry if these are wrong :’) good luck!)

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Am I right?<br> I want to know if I am right

german

Answer:

B $13

Step-by-step explanation:

Julie has 16.73 That is approximately 17 dollars

She buys a purse that is 4.12. That is approximately 4 dollars

17 -4 = 13

She will have approximately 13 dollars left

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3 years ago

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If x = 5 and 5 = y, then x = y

garri49 [273]

You are right. Transitivity means, that:
if a = b and b = c, then a = c
(here a = x, b=5 and c = y).

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3 years ago

Carmen works at a pet store. To feed 8 cats, she empties four 6-once cans of cat food into a large bowl. Carmen divides the food

Ipatiy [6.2K]

4 x 6 ounces = 24 ounces (total)
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3 years ago

Evaluate the function when x=−2, 0, and 5. g(x)=3x−2

kipiarov [429]

I hope this helps....

x=-2
g(-2)= 3(-2)-2
= -6-2
g(-2)= -8

x=0
g(0)= 3(0)-2
=-2

x=5
g(5)=3(5)-2
g(5)=13

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3 years ago

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The city of Anvil is currently home to 21000 people, and the population has been growing at a continuous rate of 4% per year. Th

Yanka [14]

Answer:

They'll reach the same population in approximately 113.24 years.

Step-by-step explanation:

Since both population grows at an exponential rate, then their population over the years can be found as:

$\text{population}(t) = \text{population}(0)*(1 + \frac{r}{100})^t$

For the city of Anvil:

$\text{population anvil}(t) = 21000*(1.04)^t$

For the city of Brinker:

$\text{population brinker}(t) = 7000*(1.05)^t$

We need to find the value of "t" that satisfies:

$\text{population brinker}(t) = \text{population anvil}(t)\\21000*(1.04)^t = 7000*(1.05)^t\\ln[21000*(1.04)^t] = ln[7000*(1.05)^t]\\ln(21000) + t*ln(1.04) = ln(7000) + t*ln(1.05)\\9.952 + t*0.039 = 8.8536 + t*0.0487\\t*0.0487 - t*0.039 = 9.952 - 8.8536\\t*0.0097 = 1.0984\\t = \frac{1.0984}{0.0097}\\t = 113.24$

They'll reach the same population in approximately 113.24 years.

4 0

3 years ago