Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


Answer: 1 and 4 are correct
Step-by-step explanation: good luck!
Answer:306
Step-by-step explanation:
since the width of the bottom square is 10, you split it between the triangles on top. You have to do this because 7 is not the whole width of the two triangles. So then the width of the triangles would be 12, 12 times 9 is 108, you'd have 216 total for both triangles and then the area of the square is 90, 90 plus 216 is 306.
Step-by-step explanation:
put some x values into the equation
i.e : -2, -1, 0 ,1 ,2
3/5 (-2) +2 = 4/5 (-2, 4/5)
3/5 (-1) +2 = 7/5 (-1, 7/5)
3/5 (0) +2 = 2 (0, 2)
3/5 (1) +2 = 2.6 (1, 2.6)
3/5 (2) +2= 3.2 (2, 3.2)
Then plot these on the graph as corodinates with the x values
B is the answer I had a class with this answer