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aleksklad [387]
3 years ago
5

recall the equation for a circle with center (h,k) and radius r At what point in the first quadrant does the line with equation

y=0.5x+4 intersect the circle with radius 4 and center (0,4)
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

9514 1404 393

Answer:

  ≈ (3.578, 5.789)

Step-by-step explanation:

We can substitute for y and solve for x.

  (x -h)^2 +(y -k)^2 = r^2 . . . equation of a circle with center (h, k), radius r

  x^2 +(y -4)^2 = 4^2 . . . . . . the equation of the given circle

  x^2 +((0.5x +4) -4)^2 = 16

  (5/4)x^2 = 16

  x = 8/5√5 . . . . multiply by 4/5 and take the square root

  y = 0.5x +4

  y = 4/5√5 +4

The point of intersection is (8/5√5, 4+4/5√5), approximately (3.578, 5.789).

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Nutka1998 [239]
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The x-values go up by 1: -2, -1, 0, 1, 2
The y values are always 3 times the previous value.
This is an exponential function.

y = a(b)^x

We need to find a and b.
Look at x = 0.
For x = 0, y = 4.

y = a(b)^x

4 = a(b)^0

Since b^0 = 1, this simplifies to

4 = a

Now we know a = 4. We have

y = 4(b)^x

Look at x = 1. For x = 1, y = 12.

12 = 4(b)^1

12 = 4b

b = 3

Now that we know a and b, we can write the function.

y = 4(3)^x

Now that you have the function written out, notice the following.
In the exponential equation we found, the number raised to x
is the number you multiply each y value to get the next y value.
In this case, each y value is 3 times the previous one, so you have 3^x.
The way you find "a" in the exponential equation is to look at the y-coordinate
when x = 0. When x = 0, b^x is 1, so b^x drops out, and you get "a" equal to
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With b = 3, and a = 4, you can quickly write:
y = 4(3)^x.
7 0
4 years ago
I need help with this one <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title=" \frac{1}{3} "
Vanyuwa [196]
To solve this questions, we can turn 2 into a fractions.

2 as a fraction is 2/1 (because 2 divide by 1 is still 2)
We can now use this to get our answer. 

1/3  ÷ 2/1 
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= 1/6          (1 x 1 / 3 x 6)

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7 0
3 years ago
*please help and explain how you got the answer!*
stepan [7]

Answer:

0

Step-by-step explanation:

A= (4-1)^3

simplify A to be 3^3

Which gives us 27

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simplify B

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Simplify the exponent first. 3*4 gives us 12 and 12-12 equals 0. Anything raised to the power of 0=1

If A-B^C is the equation we can write 27-27 raised to the power of 1 which is 0

7 0
3 years ago
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Artyom0805 [142]
<span>A=30e^.198026t
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</span>
8 0
3 years ago
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katrin2010 [14]
4(-9*x)

Multiply the two numbers
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Final answer: -36x
5 0
3 years ago
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