recall the equation for a circle with center (h,k) and radius r At what point in the first quadrant does the line with equation
1 answer:
9514 1404 393
Answer:
≈ (3.578, 5.789)
Step-by-step explanation:
We can substitute for y and solve for x.
(x -h)^2 +(y -k)^2 = r^2 . . . equation of a circle with center (h, k), radius r
x^2 +(y -4)^2 = 4^2 . . . . . . the equation of the given circle
x^2 +((0.5x +4) -4)^2 = 16
(5/4)x^2 = 16
x = 8/5√5 . . . . multiply by 4/5 and take the square root
y = 0.5x +4
y = 4/5√5 +4
The point of intersection is (8/5√5, 4+4/5√5), approximately (3.578, 5.789).
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