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Anvisha [2.4K]
2 years ago
11

Which polygon has the most sides? decagon 20-gon nonagon dodecagon

Mathematics
2 answers:
Ket [755]2 years ago
8 0

Answer:

decagon = a plane figure with ten straight sides and angles.

20-gon = In geometry, an icosagon or 20-gon is a twenty-sided polygon. The sum of any icosagon's interior angles is 3240 degrees.

nonagon = a plane figure with nine straight sides and nine angles.

dodecagon = a plane figure with twelve sides.

Step-by-step explanation:

e-lub [12.9K]2 years ago
6 0

Answer:

decagon = 10

nonagon = 9

dodecagon = 12

Step-by-step explanation:

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The two answers are the one selected and the choice |x-5| ≤ 1. The steps to solve the other equation are:
|x-5| ≤ 1
x-5 ≤ 1, x-5 ≥ 0
-(x-5) ≤ 6, x-5 is less than 0
x ≤ 6, x ≥ 5
x ≥ 4, x is less than 5
x ∈ [5,6]
x ∈ [4,5]
4 ≤ x ≤ 6
(^which was the original answer^)

7 0
3 years ago
Mary makes trail mix with bulk nuts and dried fruit. She spends $4.50 on the dried fruit. Mixed nuts cost $2.50 per pound. She h
AnnyKZ [126]

Answer: 3 pounds

Step-by-step explanation: 12 - 4.50 = 7.50 7.50/2.50=3

4 0
3 years ago
5x - 2 = 8<br> What the answer
Montano1993 [528]

Answer:

x = 2

Step-by-step explanation:

5x - 2 = 8

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x = 2

7 0
3 years ago
Read 2 more answers
PLEASE HELP! 100 POINTS!
BartSMP [9]

Answer:

Mrs. Etercsid

Step-by-step explanation:

One thing we can do is just multiply the averages by the percents in each class and compare from there.

To get from percentages to decimals, we can divide by 100.

For Mr. Tats:

Homework: 25 % -> 0.25

Participation: 10% -> 0.1

Test: 40% -> 0.4

Final: 0.25 -> 0.25

For Mrs. Etercsid:

Homework: 15% -> 0.15

Participation: 10% -> 0.1

Test: 60% -> 0.6

Final: 15% -> 0.15

We can then multiply the averages by the decimals for each teacher and add them up.

Mr. Tats:

0.25 * 81 + 0.1 * 57 + 0.4 * 93 + 0.25 * 87 = 84.9

Mrs. Etercsid:

0.15 * 81 + 0.1 * 57 + 0.6 * 93 + 0.15 * 87 = 86.7

You would get the higher grade with Mrs. Etercsid

7 0
2 years ago
I don't understand this I have spent many points on this same question so this time I will be giving brainliest for the first co
Marrrta [24]

Given:

|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|

Solution:

Complex formula:

|a+b i|=\sqrt{(a+b i)(a-b i)}=\sqrt{a^{2}+b^{2}}

Let us simplify one by one.

|3+4 i|=\sqrt{3^{2}+4^{2}}

           =\sqrt{25}

|3 + 4i| = 5

|3-4 i|=\sqrt{3^{2}+(-4)^{2}}

           =\sqrt{25}

|3 - 4i| = 5

|-3+4 i|=\sqrt{(-3)^{2}+4^{2}}

           =\sqrt{25}

|-3 + 4i| = 5

|-3-4 i|=\sqrt{(-3)^{2}+(-4)^{2}}

           =\sqrt{25}

|-3 - 4i| = 5

Substitute these in the given expression:

|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|=5+5+5+5

                                                                  =20

The solution of the expression is 20.

8 0
3 years ago
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