<span>Chris' average speed is 3.5mph: Lets take Chris' brother speed = B then Chris speed = (B+ 1) mph-------given in the question and: The average speed for covering 18 miles= chris' average speed + his brother's average speed = (B+ 1) + B since Speed = Distance covered / time taken then average speed for 18 miles can also be found by: 18 miles/3 hours = 6 miles per hour then we have; (B+ 1) + B = 6mph (B +1) = (6-B) B+B = 6-1=5 2B=5 B=5/2=2.5 mph (this is Chris' brother average speed) Hence Chris' average speed is = B+1= 2.5+1= 3.5mph</span>

8 0

2 years ago

Urgent please help .On a piece of graph paper, graph y+2<-2/3x+4

Serjik [45]

Take a look at the function $y+2=- \frac{2}{3}x+4$ . You can simplify it to $y=- \frac{2}{3}x+2$ . If x=0, then y=2 and when y=0, x=3. You obtain two points (0,2) and (3,0) that lie on the line $y+2=- \frac{2}{3}x+4$ .

Since $y+2\le - \frac{2}{3}x+4$ , the line $y+2=- \frac{2}{3}x+4$ should belong to the shaded area.

Now take point (0,0). Since $0+2\le- \frac{2}{3}\cdot 0+4$ , you can conclude that point (0,0) belongs to the shaded area.Using all these thoughts, you can make a conclusion that the correct choice is B.

8 0

2 years ago

A camera manufacturer spends $2,000 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell

hjlf

A) let the number of cameras sold per day for breakeven be x

Total daily cost = 2000 + 9x

Total daily revenue = 17x

therefore for just covering expenses both cost and revenue must be equal

2000 + 9x = 17x

2000 = 17x - 9x = 8x

x = 2000/8 = 250 cameras

b) increasing production by 50 cameras per day will give a daily profit of;

50 * (17 - 9) = 50 * 8 = $400 (seeing that the fixed daily cost of $2000 remains unchanged)

It's a

6 0

2 years ago

In parallelogram UVWX, U = 9x+15 and V = 6x+15. find W and X.

AysviL [449]

Answer:

$W = 9x + 15$ $X = 6x + 15$