We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
I think the answer is going to be a
Using proportions, it is found that the ordered pair that represents the location of the layover is given by: (2.75, 1.5).
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, the flight distance is partitioned in a ratio of 3:1, hence:
L - Nv = 3/4(Ny - Nv).
This ratio is applied for both coordinates, hence, for the x-coordinate:



x = 2.75.
For the y-coordinate:


x = 1.5.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer:
20%
Step-by-step explanation:
i divided the percentages each by 45 and so% was 4.4. 20% was the closest to 45.
You can solve this by multiplying each numerator by the answer choices and trying to divide them. I can't get the fraction maker to work at the moment, so I'll write the calculations on a separate attachment.
As you can see, the only choice that works to eliminate both fractions is the fourth choice,
50x.