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2 years ago

15

Solve using DISTANCE = RATE X TIME

2 answers:

wariber [46]2 years ago

6 0

The rate is speed which 50m/h. so he left the home at 10:00 and arrived at noon which 12:00pm so the difference is 2 hours which means he took 2 hours to get there.
to find the distance.
D=RxT = 50 x 2 = 100mile

exis [7]2 years ago

5 0

Distance = Rate * Time

The rate he is going at is 50 mph
The time it took is 10 am to 12 pm. That is 2 hours.

Distance = 50 mph * 2 hr

Distance = 100 miles

Mike drove 100 miles.

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1 year ago

Find an explicit formula for the arithmetic sequence below.<br> 9, 39/4, 21/2, 45/4, 12, 51/4,...

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2 years ago

3(x - 2) + 48 = -3x

kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

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3 years ago

Solve for j.<br>-2j + 39 = 111<br>j=<br>

olga_2 [115]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

Vesna [10]

Answer:

$c = 11$

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

$a = b= 5$

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

$a + b > c$

$a + c > b$

$b + c > a$

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: $a = b= 5$

$5 + 5 > c$ $===>$ $10 > c$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

The results of the inequality is: $10 > c$ and $c > 0$

Rewrite as: $c > 0$ and $c < 10$

$0 < c < 10$

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

$c = 11$ , since no options are given

8 0

2 years ago