All categories

3 years ago

Solve for b a=b-4/c

Mathematics

1 answer:

Agata [3.3K]3 years ago

6 0

Answer:

Rewrite the equation as

Subtract

from both sides of the equation.

−

Divide each term by

and simplify.

Tap for more steps...

−

Step-by-step explanation:

You might be interested in

A(n) _______ is a mapping that does not change the size of the original figure.

d1i1m1o1n [39]

Answer:

A(n) isometry is a mapping that does not change the size of the original figure.

5 0

3 years ago

Read 2 more answers

A scientist has 350 mg of a radioactive material. The material will cut in half every month. After how many months will there be

Zanzabum

The answer would be about 9 months.

6 0

3 years ago

Isoke is solving the quadratic equation by completing the square.

Alexandra [31]

Step-by-step explanation:

10 is the value of A ......

6 0

3 years ago

Read 2 more answers

What is the common ratio for the sequence 28,14,7,3.5 ?

wolverine [178]

Answer:

Its 2

Step-by-step explanation:

7 0

2 years ago

A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati

I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

$\frac{dT}{dt}=k*(T_r-T)$

If we rearrange and integrate

$\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}$

We know that at time 0, the temperature of the drink was 52°F. Then we have:

$T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20$

We also know that at t=2, T=55°F

$T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08$

The model for the temperature of the drink can be written as

$T=72-20e^{-0.08t}$

7 0

3 years ago