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NemiM [27]
3 years ago
14

Complete the table to summarize what you know about each player's throw: (2 points: 1 point for each row of the chart) tre and h

ector
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

Tre: Tre’s position was on the pitcher’s mound and he threw the ball to 3rd base.

Hector: Hector’s position was in right field and he threw the ball to 2nd base.

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Solve 20 - x/3 = x/2 , put the number only in the box.
Nikitich [7]

Answer:

<h2>x = 24</h2>

Step-by-step explanation:

20 -  \frac{x}{3}  =  \frac{x}{2}

Multiply through by the LCM that's 6 in order to eliminate the fraction

That's

6 \times 20 - 6 \times  \frac{x}{3}  = 6 \times  \frac{x}{2}  \\ 120 - 2x = 3x

Using the addition property add 2x to both sides of the equation

That's

3x + 2x = 120 + 2x - 2x \\ 5x = 120

<u>Divide both sides by 5</u>

\frac{5x}{5}  =  \frac{120}{5}

We have the final answer as

<h3>x = 24</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
The inequality _______________ represents the number of boxes of lightbulbs that Cecil started with.
Vedmedyk [2.9K]

Answer:

The inequality 14

Cecil had 14 boxes of lightbulbs when he started

I think not 100% sure

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
g A coin where the probability of heads is 0.3 is flipped 2000 times. Use the normal approximation to the binomial distribution
matrenka [14]

Title:

<h2>See the explanation.</h2>

Step-by-step explanation:

The coin is to be flipped 2000 times.

The probability of getting a head is 0.3.

It is given that, we need to get a head in between 575 and 618 times.

If we will get 575 heads then we will get (2000 - 575) tails.

Hence, if we take that we want to get n times head, then we will get (2000 - n) times tail.

The probability of not getting a head is (1 - 0.3) = 0.7.

The probability of getting n times head is ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}.

The required probability is ∑ ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}, where 575 \leq n \leq 618.

5 0
3 years ago
July 15: Hire part-time helper to be paid $12 per hour. Pay periods are the 1st through the 15th and 16th through the end of the
nikklg [1K]

Answer:

The information above is just a part of a long question.The main question is  found in the attached as well as the answer following a step by step methodical approach.

Step-by-step explanation:

Take a good at the full question before venturing into the statements prepared so as to have a thorough understanding of the requirements and how the answers provided have touched upon the requirements.

Download xlsx
3 0
3 years ago
c. Using a standard deck of 52 cards, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually
dybincka [34]

Answer:

True

Step-by-step explanation:

If two events X and Y are mutually exclusive,

Then,

P(X∪Y) = P(X) + P(Y)

Let A represents the event of a diamond card and B represent the event of a heart card,

We know that,

In a deck of 52 cards there are 4 suit ( 13 Club cards, 13 heart cards, 13 diamond cards and 13 Spade cards )

That is, those cards which are heart can not be diamond card,

⇒ A ∩ B = ∅

⇒ P(A∩B) = 0

Since, P(A∪B) = P(A) + P(B) - P(A∩B)

⇒ P(A∪B) = P(A) + P(B)

By the above statement,

Events A and B are mutually exclusive,

Hence, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually exclusive event is a true statement.

4 0
3 years ago
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