<h2>Monosaccharides</h2>
Explanation:
Monosaccharides are the simplest form of sugars found in innumerable common food items such as honey, cane sugar, fruits
Monosaccharides are divided into two groups depending on the presence of functional groups,if aldehyde group is present then it is known aldoses and if ketone group is present then it is known as ketoses
On the basis of carbon atoms they can be classified as: triose(3),tetrose(4),pentose(5),hexose(6) and so on
a. erythrose : tetrose ketose-It is not correctly paired because erythrose is a tetrose monosaccharide which has one aldehyde group hence is an aldose
b. dihydroxyacetone : triose ketose-It is correctly paired;it is an aldose-ketose pair
c. erythrulose : tetrose aldose-It is not correctly paired because erythrulose is a tetrose monosaccharide having ketone as functional group hence is a ketose
d. fructose : hexose ketose-it is correctly paired;It is an anomer because in D-fructose carbonyl group is at C-2 hence C-2 is the anomeric carbon
e. ribose : hexose aldose-it is not correctly paired because ribose is an aldo pentose not hexose;ribose is an aldo-ketose pair
f. glyceraldehyde : triose aldose-it is correctly paired;an aldo group
Answer:codominance
Explanation: Both genes will be expressed equally without overshadowing the other
Answer:
Explanation:
Honey-colored eyes A is dominant over blue-colored eyes a.
A homzygous honey-colored male (AA) had a baby with blue-eyed female (aa).
AA x aa
Offspring Aa Aa Aa Aa
1. Since A is dominant over a, <u>all the expected offspring would have honey-color eyes with Aa genotype.</u>
2. The genotype of the homzygous honey-color eyes father would be AA while that of the blue-eye mother would be aa.
please help there’s 3 questions at the bottom left.
False that is not correct
