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3 years ago

A family has 5 children. Compute the probabilities of the following events:

Mathematics

2 answers:

Bezzdna [24]3 years ago

7 0

Answer:

1/16,807 chance that they all will be born on Friday

Probably 5/7, but don't take my word for it.

Step-by-step explanation:

There are 7 days of the week.

There is a 1/7 chance for one kid to be born on a certain day of the week.

We can attach an exponent of 5 since the 1/7 is a constant, and I'm not going to bother typing the same thing over and over again.

(1/7)^5 = 1/16,807.

The probability of all of them being born on Friday or anyday is 1/16,807.

The probability of each person being born on a different day of the week is probabily going to be 5/7, but it could be different, because you need to factor in the requirement that they are not born on the same day.

I can guarantee that the first question is probably correct, but not the second.

Arlecino [84]3 years ago

4 0

I think the answer is 10% and 90%

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3 years ago

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Maddy has a bag of 36 marbles. The probability of picking green is 1 in 2, the probability of picking red is 1 in 3, and the pro

KonstantinChe [14]

Answer: 1 in 18

This is the same as writing the fraction 1/18

==============================================================

Explanation:

Since she has 36 marbles total, and the probability of picking green is 1 in 2, this means (1/2)*36 = 18 marbles are green.

Then she also has (1/3)*36 = 12 red marbles and (1/9)*36 = 4 blue marbles.

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3 years ago

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3 years ago

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Answer:

f (x) = { 19 + 0.39(x - 300), x > 300

Step-by-step explanation:

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3 years ago