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3 years ago

A family has 5 children. Compute the probabilities of the following events:

Mathematics

2 answers:

Bezzdna [24]3 years ago

7 0

Answer:

1/16,807 chance that they all will be born on Friday

Probably 5/7, but don't take my word for it.

Step-by-step explanation:

There are 7 days of the week.

There is a 1/7 chance for one kid to be born on a certain day of the week.

We can attach an exponent of 5 since the 1/7 is a constant, and I'm not going to bother typing the same thing over and over again.

(1/7)^5 = 1/16,807.

The probability of all of them being born on Friday or anyday is 1/16,807.

The probability of each person being born on a different day of the week is probabily going to be 5/7, but it could be different, because you need to factor in the requirement that they are not born on the same day.

I can guarantee that the first question is probably correct, but not the second.

Arlecino [84]3 years ago

4 0

I think the answer is 10% and 90%

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2 years ago

F(x) = 10*(x + 5)²<br>f(5) = ?

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<h2>♪Answer : </h2>

»f(x) = 10*(x + 5)²

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2 years ago

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A one-year membership to Metro Gym costs $460 including is a fee of $100. How much will a customer pay monthly

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3 years ago

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2 years ago

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How do i calculate? All the way to s_75. It’s so long

mina [271]

Answer:

-675

Step-by-step explanation:

The sum can be broken into parts that you know. Here, one of those parts is the sum of numbers 1 to n. That sum is given by n(n+1)/2.

$\displaystyle S_{75}=\sum\limits_{n=1}^{75}{(67-2n)}=\sum\limits_{n=1}^{75}{67}-2\sum\limits_{n=1}^{75}{n}\\\\=75\cdot 67-2\dfrac{75(75+1)}{2}=75(67-76)\\\\=\bf{-675}$

Another way to do this is to realize the sequence of numbers is an arithmetic sequence with a first term of 65 and a last term of 67-2·75 = -83.

The sum of an arithmetic sequence is found by multiplying the number of terms by their average value. Their average value is the average of the first and last terms.

The average value of those 75 terms is (65 +(-83))/2 = -9, so their sum is ...

75(-9) = -675

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3 years ago