You want the saturated vapour pressure,
P
SVP
.
Explanation:
This is a function of temperature only, and at
283
⋅
K
this site reports that the vapour pressure of water,
P
SVP
, is
9.2
⋅
m
m
⋅
H
g
.
And so,
P
Measured
=
P
gas
+
P
SVP
,
P
Gas
=
P
Measured
−
P
SVP
750
⋅
m
m
⋅
H
g
−
9.2
⋅
m
m
⋅
H
g
=
741.8
Explanation:
such bad questions , how it could be around ???
M ....6,022*10^22 molecules
2,30g .......3,01*10^22 molecules
or 1 mole has 6,022*10^22 molecules so (2,30/Molar mass) = nr of moles with 3,01*10^22 molecules
which will lead to the same thing.
M= 4,6
Answer:
At concentration of copper ions will begin precipitating out.
So, the precipitate will be of CuI.
Explanation:
For Copper chloride
Concentration of chloride ions =
The solubility product of CuCl =
S 0.021 M
To start a precipitation of CuCl we need concentration of copper.
For Copper iodide
Concentration of iodide ions =
The solubility product of CuI =
S 0.017 M
To start a precipitation of CuI we need concentration of copper.
The copper ion which will begin to precipitate out from the solution will be the precipitate with less concentration of copper ion.So, the precipitate will be of CuI. At concentration of