Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.
For instance, a solid white material (A) is heated in the absence of air, decomposing to form a new white material (B) and gas (C). Gas (C) has the same properties as the products when carbon is burned in an excess of oxygen (CO2). How can we determine whether A, B, and C are elements or compounds? A would be a compound since it was broken down into B and C. So how do we determine B and C?
A compound can be decomposed, for the reason that a compound is composed of 2 or more elements. On the contrary, an element cannot be decomposed.
Answer:
Subatomic particles making up an atom
Explanation:
Atom is the smallest unit of any matter
An atom consists of three subatomic particles - Protons, Neutrons, Electrons. Major atomic mass is in the nucleus ie a tiny deep area at the centre. Nucleus consists nucleons, which includes protons (positively charge) & neurons (neutrally charged). Negatively charged electrons are outside the central nucleus.
Answer:
The diluted solution is 0.65 M
Explanation:
Dilution formula to solve the problem is:
M concentrated . V concentrated = M Diluted . V diluted
We can also make a rule of three though.
In 1000 mL of concentrated solution, we have 13.1 moles of HNO₃
So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃
This moles are also in 0.500 L of diluted solution, the new molarity will be:
0.327 mol / 0.5L = 0.65 M
Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.
If we replace in the formula
13.1 M . 25 mL = 500 mL . M diluted
M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M
Answer:
Five significant figures.
Explanation:
The given measurement have five significant figures 52301.
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.
Zero between the non zero digits are consider significant like 104 consist of three significant figures.
The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.
Answer:
Option C
Explanation:
A) A chemical equation is simply the symbolic representation of a chemical reaction using the form of symbols and formulae. Thus, option A is not the answer.
B) A product is the substance that shows at the end of a chemical reaction. Thus, option B is not the answer.
C) Law of conservation of mass in chemistry states that even in chemical reactions or physical transformations, that mass cannot be created nor destroyed. Which means that mass is conserved. This has nothing to do with chemical change demonstrated chemical reactions. Thus, option C is correct.
D) reaction rate is the speed that a chemical reaction occurs. Thus, options D is not correct.