A-1538=1074
a=1538+1074
a=2612
b+718=1074
b=1074-718
b=356
2000-c=1074
c=2000-1074
c=926
2612-356+926=3182
Answer
(3,-2)
Explanation step by step
<em>y</em><em>=</em><em> </em><em> </em><em>-</em><em>2</em><em>x</em><em>-</em><em>9</em>
<em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>(</em><em>-</em><em>6</em><em>,</em><em>1</em><em>)</em><em>-</em><em>9</em>
<em>=</em><em> </em><em>(</em><em>1</em><em>2</em><em>,</em><em>-</em><em>2</em><em>)</em><em>-</em><em>9</em>
<em>=</em><em>(</em><em>3</em><em>,</em><em>-</em><em>2</em><em>)</em>
First you add all of them and then divide by how much numbers you have
Answer: 1025.16666667
Answer:
m = 6
Step-by-step explanation:
Given
5m + 30 = 60 ( subtract 30 from both sides )
5m = 30 ( divide both sides by 5 )
m = 6
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
