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Answer:
1) 402.7 grams. This estimate is called the sample mean.
2) (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Explanation:
sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams
1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.
2) c = 99% = 0.99
α = 1 - 0.99 = 0.01
.
The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).
.
The margin of error (e) = 
The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Answer: I am pretty sure it's RAM
Explanation:
I'm not 100% positive bc I haven't gotten my scores back yet but I think that's it.
To convert binary fraction to decimal fraction, we first write the given
.1011 (base 2)
The process of conversion is to break down to its decimal constituent,
.1011 (base 2) = (1*2^-1)+(0*2^-2)+(1*2^-3)+(1*2^-4)
.1011 (base 2) = 0.5 + 0 + 0.125 + 0.0625
.1011 (base 2) = 0.6875 (base 10)
<em>ANSWER: 0.6875 (base 10)</em>