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allsm [11]
3 years ago
12

Z is the center of the circle. Suppose that QR = 15, SR = 15, UZ = 22, and VZ = 5x - 3. Find x and SV.

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
6 0
Uhhhh i don’t know. Here for points
Serjik [45]3 years ago
5 0

Answer:

jdwfmejbkdcdl

Step-by-step explanation: you did it to me

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The equation shown on the table is y=2x
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Compare: 10 quarts and 2.5 gallons *
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10 quarts = 2.5 gallons
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Factorize completely 3x-2x^-x+2 ( three x -two x square-x+2)
Phantasy [73]

Answer:

-2(x^2 - x - 1).

Step-by-step explanation:

3x - 2x^2 - x + 2

= 2x - 2x^2 + 2

= -2(x^2 - x - 1)

6 0
3 years ago
Please help! 3 Questions please show how you solved the problem
Masteriza [31]

Answer:

1)  (-y^2-4y-8+4y^2+6y-3)

2)  32x^5y^4z^2

3)  x^3-9x^2+14x+24

Step-by-step explanation:

Given the expression we have to simplify the expression

1)   (-y^2-4y-8)-(-4y^2-6y+3)

⇒ (-y^2-4y-8+4y^2+6y-3)

Combining like terms, we get

⇒ 3y^2+2y-11

2.)    (2x^2y^3z^2)(4xy.4x^2)

⇒ (2x^2y^3z^2)(16x^3y)

⇒ 32x^5y^4z^2

3.)   (x-4)(x^2-5x-6)

⇒ x^3-5x^2-6x-4x^2+20x+24

⇒ x^3-9x^2+14x+24

5 0
3 years ago
The graph of the equation y = m^x passes through the point
Alexeev081 [22]

The graph of the equation y = m^x passes through the point (1, m)

<h3>Equation of a graph</h3>

Given the equation of a graph expressed as y = m^x

We need to determine the coordinate point that lies on this graph.

If x = 1, substitute into the formula to have:

y =m^1

y = m

Hence the required coordinate will be (1, m)

Learn more on equation of graph here: brainly.com/question/24894997

3 0
2 years ago
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