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strojnjashka [21]
3 years ago
12

32 divided by a number c

Mathematics
1 answer:
Drupady [299]3 years ago
3 0
32/C would be the answer-
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Dima020 [189]
You could convert them into improper fractions first. 7 7/8 should become 63/8 and 3 1/4 should become 13/4. Then, change both fractions so they share a common denominator. I'll use 8. 
63/8-26/8 = 37/8, which is then converted into 4 5/8.
Hope that helped you.
8 0
3 years ago
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What is the simplified form of 15 times x to the fifth power over 20 times y to the sixth power times the fraction 6 times y to
VARVARA [1.3K]

Answer:

no

Step-by-step explanation:

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F(x)=2x^2-5x+4 find f(-4) how do i do that?
Mars2501 [29]

Answer:

f(4)=2(x)^2-5(4)+4

Step-by-step explanation:

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3 years ago
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Please help me with geometry
spayn [35]
For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

------------------------------------------------------

For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

3 0
3 years ago
Can you explain please?
tia_tia [17]

Answer: To right in different numbers

Step-by-step explanation:

7 0
3 years ago
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