Answer:
PQ = √(7-2)²+(3-5)²
= √ 5²+(-2)²
= √ 25+4
=√29 units
Hope it helps !
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Answer:
OC = 10.07 CM
BC = 9.73 cm
area triangle OAB = 97.98 cm^2
area of sector OADB = 150.05 cm^2
% of diagram that is shaded = 65%
Step-by-step explanation:
cos 44 = OC/14
0.71934(14) = OC = 10.07
sin 44 = BC/14
0.6947(14) = BC = 9.73
area of sector OADB = (88/380)(Pi)14^2) =150.05
area triangle OAB = (OC)(BC)(0.5)(2) = 97.98
% of diagram shaded = 97.98/150.05 = 0.65 = 65%
Hello :
45ax²<span>+27 ax+18a=9a
45ax² +27ax +9a =0
</span><span>this statement is :
</span><span> - if : a= 0 this expression = 0
- if : a </span>≠ 0 this expression = 45x²+27x+9
Answer:
It will take one day and they will each sell 20 cars.
Step-by-step explanation:
Choose variables to represent each thing of interest:
- Fairfax = F
- Mason = M
- days = d
F = 19 + 1(d)
M = 18 + 2(d)
The goal is for F and M to equal one another, so set the equations equal to one another.
19 + 1d = 18 + 2d
1 = d
So, it will take one day.
Now, solve for F and M
F = 19 + 1(1) = 20
M = 18 + 2(1) = 20
Step1: Find the area of the triangular lawn
Given, base of the triangle is y metres and the height is z metres
Area of the triangle =
2
1
× base × height
Therefore, area of the triangular lawn =
2
1
yz metre
2
.
Step 2:Find the cost of planting the grass
Rate of planting the grass is Rs. x per square metre.
Therefore, the cost of planting the grass on a triangular lawn =cost per square meter × area of the triangular lawn
=x×
2
1
yz=
2
1
xyz
Hence, the cost of planting the grass on a triangular lawn whose base is y metres and height is z metres is Rs.
2
1
x y z.
Step-by-step explanation:
