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3 years ago

Help please! (no links)

Mathematics

1 answer:

disa [49]3 years ago

3 0

EZ is 24.5
Happy is 25

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3x-2y=-1 and 3x-2y=9 solve using elimination

luda_lava [24]

You can put them vertically
then subtract them
but if you do it, it will be 0=-10 that doesn't make sense.
So the answer is that there is no answer!

3 0

3 years ago

A share of ABC stock was worth $70 in 2011 and only

Bezzdna [24]

Answer:

5v + 32y = 350

Step-by-step explanation:

Let, the year counting starts in 2011 and represented by y.

So, the share of ABC stock value was $70 at y = 0. And in the year 2016 i.e. y = (2016 - 2011) = 5, the share worth $38.

If there is a linear relationship between the number of years since 2011 i.e. y and the value of the share of ABC stock i.e. v, then we can write the equation of this situation as

$\frac{v - 70}{70 - 38} = \frac{y - 0}{0 - 5}$

⇒ 5v - 350 = - 32y

⇒ 5v + 32y = 350 (Answer)

6 0

2 years ago

In the scalene triangles shown, 2P = 2).

Black_prince [1.1K]

Answer:

I guess (c) is your answer. thanks!!

8 0

3 years ago

BRAINIEST TO WHOEVER RIGHT

Scilla [17]

Answer:

A C and E

if you need explanation you can comment down

6 0

3 years ago

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find

Serga [27]

Answer:

Required solution is $y(x)=1+A\cos x+B\sin x$ where A and B are constants.

Step-by-step explanation:

Given nonhomogenous differential equation is,

$y''(x)+y'(x)=1\hfill (1)$ with $y_1(x)=1$

To find another solution, consider $m=\frac{\partial}{\partial x}$ be such that,

$m^2+1=0\implies m=\pm i$

Hence,

$C.F=A\cos x+B\sin x$ where A and B are constants.

Let $D=\frac{\partial}{\partial x}$

$P.I=\frac{1}{1+D^2}(1)$

$=(1+D^2)^{-1}(1)$

$=(1-D^2+.....)(1)=1$

Hence,

$y(x)=1+A\cos x+B\sin x$ where A and B are constants.

which is required solution.

6 0

3 years ago